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snow_tiger [21]
3 years ago
11

Write an equivalent expression for (116)5.

Mathematics
1 answer:
Radda [10]3 years ago
3 0

Answer:

580 is the answer i thik its helps u tqq

You might be interested in
(5i^{2} -3) * (6i *2^{6})
Rus_ich [418]

i^2 = -1

Replace i^2 with -1 and simplify:

(5(-1) - 3) * (6i*2^6) =

(-5 - 3) * (6i * 64) =

-8 * 384i =

-3072i

5 0
3 years ago
What are the zeros of this function?
Nina [5.8K]

Answer:

C

Step-by-step explanation:

The zeros are the values of x on the x- axis where the graph crosses.

the graph crosses the x- axis at 0 and 5

then the zeros are x = 0 and x = 5 → C

4 0
2 years ago
Pls help! Brainliest for first correct answer!
Triss [41]

Answer:

36 kg

Step-by-step explanation:

Let m = mass of green tea.

The total mixture should be (18*3.5+2.6*m)/(18+m) = 2.9

The numerator is $, denominator is kg

Therefore 63+2.6m = 52.2+2.9m

0.3m = 10.8

3m = 108

m = 36

6 0
3 years ago
Any answers? No need for an explanation if you want to sure, the answer would be appreciated!
KIM [24]

Answer:

B

Step-by-step explanation:

B: it is only a single equation

8 0
2 years ago
Recall the experiment comparing patients 4 weeks after surgery for carpal
dimulka [17.4K]

Answer:

4. H0: u1= u2    Ha; u1≠ u2

5. The smaller value of p supports the null hypothesis.

Step-by-step explanation:

4. The null and alternate hypotheses are

H0: u1= u2   i.e there no difference between the mean pinch strengthof the two surgeries

against the claim

Ha; u1≠ u2   i.e there a difference between the mean pinch strengthof the two surgeries

It can be written like this as well

H0: u1 -u2= 0   i.e there no difference between the mean pinch strengthof the two surgeries

against the claim

Ha; u1 -u2≠ 0   i.e there a difference between the mean pinch strengthof the two surgeries

Part 5. The test having a p- value less than 0.05  tells that the null hypothesis cannot be rejected. Theres no evidence to reject the null hypothesis.

The smaller value of p supports the null hypothesis.

3 0
2 years ago
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