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snow_tiger [21]
3 years ago
11

Write an equivalent expression for (116)5.

Mathematics
1 answer:
Radda [10]3 years ago
3 0

Answer:

580 is the answer i thik its helps u tqq

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How would solve 2s + s = 36
Lesechka [4]
2s + s = 36
3s = 36
s = 36/3
s = 12
7 0
3 years ago
If you have a scoop that holds 3 6 36 cup, and a recipe calls for 2 3 6 236 cups of water, then how many scoops would you need t
exis [7]
Seven scoops with some water left over
6 0
3 years ago
100 POINTS! I REPEAT 100 POINTS! PLEASE HELP!
AURORKA [14]
First you need to find the area of the lawn. To find the area of a square, you multiply two sides together. You have two sides given, which is super helpful.

I put in my calculator, (40+4/5)x(50+7/8) and this gave me the answer of 2075.7.
You need to then divide that number by 500, and divide it by 300, and then round up, cause if you round down you’re not gonna have enough seed.

2075.7/500 = 4.1514, but then this needs to be rounded up or he’ll be 0.1514 short. So he needs 5 bags for the highest setting.

2075.7/300 = 6.919, so for the lowest setting, he needs 7 bags of seed.

This should be correct.

Hope this helps :)
6 0
3 years ago
A bucket contains stones and seashells. There are 30 seashells in the bucket and the ratio of stones to seashells is 4 : 3. Find
sergejj [24]

Answer:

There should be 40 stones in the bucket

Step-by-step explanation:

4:3 = x:30

3*10 = 30

4*10 = 40

x = 40

Hopefully that helped.

3 0
3 years ago
Use a Pythagorean identity to rewrite the equation below using only the function sin θ. Then find the value of r if θ=30°,60°, a
zepelin [54]
\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
r=4sin(\theta )cos^2(\theta )\implies r=4sin(\theta )[1-sin^2(\theta )]
\\\\\\
r=4sin(\theta )-4sin^3(\theta )\qquad \qquad 
\begin{cases}
r=4sin(30^o)-4sin^3(30^o)\\
r=4sin(60^o)-4sin^3(60^o)\\
r=4sin(90^o)-4sin^3(90^o)
\end{cases}

\bf \begin{cases}
r=4\left( \frac{1}{2} \right)-4\left( \frac{1}{2} \right)^3\\\\
r=4\left( \frac{\sqrt{3}}{2} \right)-4\left( \frac{\sqrt{3}}{2} \right)^3\\\\
r=4(1)-4(1)^3
\end{cases}\implies 
\begin{cases}
r=2-\frac{1}{2}\\\\
r=2\sqrt{3}-\frac{3\sqrt{3}}{2}\\\\
r=4-4
\end{cases}\implies 
\begin{cases}
r=\frac{1}{2}\\\\
r=\frac{\sqrt{3}}{2}\\\\
r=0
\end{cases}
6 0
3 years ago
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