What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
Answer: There are several information's of immense importance already given in the question. Let us write them down first.
Diameter of the cylinder = 6 inches
Then
Radius of the cylinder = 3 inches.
Height of the cylinder = 3 * radius
= 3 * 3
= 9 inches
Volume of the cylinder = (pi) * (Radius)^2 * Height
= 3.14 * (3)^2 * 9
= 3.14 * 9 * 9
= 254.34 cubic inches
When 10 meters of something is divided into 6 equal parts,
then each part is (1,666 and 2/3) millimeters long.
A). Whole number . . . No, that's not a whole number
B). Interger . . . No, there's no such thing as an 'interger'.
C). Rational number . . . Yes, its the ratio of 10,000 to 6 .
D). Irrational number . . . No, it's not irrational.
120 the formula for interior angles of a shape is ((n-2)180)n
3x² - 39x + 36
3(x²) - 3(13x) + 3(12)
3(x² - 13x + 12)
3(x² - 12x - x + 12)
3(x(x) - x(12) - 1(x) + 1(12))
3(x(x - 12) - 1(x - 12))
3(x - 1)(x - 12)
