Answer:
Step-by-step explanation:
a)
i)
<u>Use the law of cosines:</u>
ii)
<u>Use the law of sines:</u>
- sin ∠A / PB = sin ∠P / AB
- sin ∠A / 100 = sin 80 / 107.31
- sin ∠A = 100 sin 80 deg / 107.31
- sin ∠A = 0.92
- ∠A = arcsin 0.92
- ∠A = 67° (rounded)
iii)
<u>Bearing of B from A:</u>
b)
<u>PB is longer distance. Time to reach B:</u>
- t = d/s
- t = 100/20 = 5 hours
<u>The speed s of the slower ship:</u>
- s = d/t
- s = 60/5 = 12 km/h
Remember: The formula for surface area for cylinders are S= 2πrh + 2πr²
The 2πr² represents the circular parts of the cylinder.
First, let's find the lateral side of the cylinder.
→ 2 (3.14)(6)(15) = 565.2
Next, find the circular parts.
→ 2 (3.14)(6²)
→ 2 (3.14)(36) = 226.08
Add the two answers together.
→565.2 + 226.08 = 791.28
Round.
Your final answer is 791.3 in²
I hope this helps!
Answer:
Step-by-step explanation:
Answer:
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Step-by-step explanation:
We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 35
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.0322
The margin of error is:
M = T*s = 2.0322*30 = 60.97
The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes