-5x + y = -5.....multiply by -2
-4x + 2y = 2
---------------
10x - 2y = 10 (result of multiplying by -2)
-4x + 2y = 2
-----------------add
6x = 12
x = 12/6
x = 2
-5x + y = -5
-5(2) + y = -5
-10 + y = -5
y = -5 + 10
y = 5
solution is (2,5)
r - 4/5r = 1/5r + 1
Subtract 1/5r from each side: r - 4/5r - 1/5r = 1
Combine all the 'r' terms on the left side:
r - 5/5r = 1
r - r = 1
0 = 1
There is no value of 'r' that can make ' 0 = 1 ' a true statement.
So the equation has <em>no solution</em>.
Answer:
A.
Step-by-step explanation:
Answer : Option D is correct i.e [2.5,4]
Explanation :
Suppose our function is f(x)
then the value of f(x) is minimum where
it reaches -0.44 and 3 with two different intervals .
As we know that for finding the local minimum ,
the criteria is that f'(x)=0 .
So, here
f'(-0.44)=0 and
f'(3)=0
both are the local minimum point for the function f(x)
but -0.44 is the global minimum point .
In our case for [2.5,4] is the required interval where f(x) reaches its local minimum.
