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Anit [1.1K]
3 years ago
11

Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!!

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0

Answer:

(x+5) meters long

Step-by-step explanation:

x^2 + 10x+25

We recognize that this is a perfect square trinomial

a^2 + 2ab+b^2 = (a+b)^2

x^2+2*5*x+5^2 = (x+5)^2

Since this is a square

A = s^2 where s is the side length

(x+5) ^2 =s^2

Each side is (x+5)

djverab [1.8K]3 years ago
3 0

Answer:

x+5

Step-by-step explanation:

Side is equal to sqrt area

= sqrt x^2 +10x + 25

= x+5

So one side of the square is x+5 metres

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Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not
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Answer: \left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-3-2}{4-1}

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Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = -\frac{5}{3}(x - 1)

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Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ -\frac{5}{3}x + \frac{11}{3}

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8 ___ \frac{1}{3}

8 > \frac{1}{3}

so ≤ makes the statement False

⇒ y ≤ -\frac{5}{3}x + \frac{11}{3}

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.  

y < 8   or  x > -2 are two examples.


---> I just realized that the system can be simpler than what I did above:

\left \{ {{x>-2} \atop {y < 8}} \right



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