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Eva8 [605]
3 years ago
14

Fred went to catch a minimun of 2 pounds of fish.He caught 5/16 pounds.He caught another fish that was 7/8 pounds.How many pound

s of fish did he catch so far? What shoud be the minimun weight of the third fish so that he can catch at least 2 pounds of fish in total?
Mathematics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

1 3/16

Step-by-step explanation:

5/16 + (7/8= 14/16)

14/16 + 5/16= 19/16

16/16 = 1

3 LEFT OVER

1 3/16

katrin [286]3 years ago
4 0

Answer:

He caught 1 3/16 pounds of fish.

Minimum weight = 13/16 pounds.

Step-by-step explanation:

So far he caught 5/16 + 7/8

= 5/16 + 14/16 = 19/16

= 1 3/16 pounds.

Minimum wight of the third fish = 2 - 1 3/16

=  32/16 - 19/16

= 13/16 pounds.

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Step-by-step explanation:

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8 0
3 years ago
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Can u guys PLEASE do this question.
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\frac{4.5}{100}  \times 2000

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4 0
3 years ago
Two terms of an arithmetic sequence are a10=16 and a35=66 find the sum of the first 75 terms
andrew11 [14]

The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.  

<h3>How to find the sum of terms using Arithmetic sequence formula</h3>

aₙ = a + (n - 1)d

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore, let's find a and d

a₁₀ = a + (10 - 1)d

a₃₅ = a + (35 - 1)d

Hence,

16 = a + 9d

66 = a + 34d

25d = 50

d = 50 / 25

d = 2

16 - 9(2) = a

a = 16 - 18

a  = -2

Therefore, let's find the sum of 75 terms of the arithmetic sequence

Sₙ = n / 2 (2a + (n - 1)d)

S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)

S₇₅ = 37.5 (-4 + 148)

S₇₅ = 37.5(144)

S₇₅ = 5400

learn more on arithmetic sequence here: brainly.com/question/1687271

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