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Agata [3.3K]
2 years ago
14

Simplify the given expression. –10xy(4xy3 – 7xy + 9y2)

Mathematics
1 answer:
Drupady [299]2 years ago
6 0

Answer:

\large\boxed{-40x^2y^4+70x^2y^2-90xy^3}

Step-by-step explanation:

Use the distributive property <em>a(b + c) = ab + ac</em>:

-10xy(4xy^3-7xy+9y^2)\\\\=(-10xy)(4xy^3)+(-10xy)(-7xy)+(-10xy)(9y^2)\\\\\text{use}\ a^na^m=a^{n+m}\\\\=-40x^{1+1}y^{1+3}+70x^{1+1}y^{1+1}-90xy^{1+2}\\\\=-40x^2y^4+70x^2y^2-90xy^3

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v¹= -15, v²= -1

Step-by-step explanation:

there's 2 solutions to this

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I need help with this problem! Please Help<br> t=-2.74 + sqrt(2.74^(2)-4*-4.9*(-10)) -: 2*-4.9
Ulleksa [173]

Answer:

Step-by-step explanation:

t=(-2.74 + sqrt(2.74^(2)-4*-4.9*(-10))) / -2*-4.9

t=(-2.74 + sqrt(7.5076-4*+49))/9.8

t=(-2.74 + sqrt(7.5076+45))/9.8

t=(-2.74 + sqrt(52.5076))/9.8

t=(-2.74/9.8)+(sqrt(52.5076))/9.8

this is simplest form, next will be rounded answers

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Which statement about these triangles is true
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2 years ago
What is the completely factored form of f(x)=x^3-7x^2+2x+4
xxMikexx [17]

Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)

Steps:

x^3-7x^2+2x+4

Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}

\frac{x^3-7x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}

\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4

\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

8 0
2 years ago
What is 1,634÷19 in division?
erik [133]
86

86*10= 860
86*9= 774
860+774= 1634
5 0
3 years ago
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