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3 years ago

13

What to do in the the following question

1 answer:

Anon25 [30]3 years ago

6 0

The answer would be SSA because you have line MC is congruent to line GE, then line EO is congruent to line CB, and then you have angle O is congruent to angle B

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2 Points<br> What is one role of Congress in determining the federal budget?

RideAnS [48]

Answer:

Congress must create and pass numerous funding bills each fiscal year to keep the federal government open.Each year, Congress works on a federal budget for the next fiscal year. The government's fiscal year runs from October 1 of one year to September 30 of the next. The budget includes a detailed spending plan.

3 0

3 years ago

Plz solve, free brainlest if you solve, this my little sis’s homework

faust18 [17]

Answer:

5x6=30

6x50=300

those are two lol.

3 0

3 years ago

A group consists of fivefive men and sevenseven women. FourFour people are selected to attend a conference.

exis [7]

Answer:

Step-by-step explanation:

a.

4 people can be selected in ways=12 P4=12×11×10×9=11880

b.

4 women can be selected in ways=7P4=7×6×5×4=840

c.

$P=\frac{840}{11880} =\frac{7}{99}$

6 0

3 years ago

The Venn diagram shows the results of two events resulting from rolling a number cube.

tankabanditka [31]

Answer:

$P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{1}{3}$

$P(A) =\frac{2}{3}$

$P(B) =\frac{1}{2}$ .

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

$P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}$

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

$P(A) = \frac{4}{6} = \frac{2}{3}$

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

$P(B) = \frac{3}{6} = \frac{1}{2}$ .

Now

$P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}$

6 0

3 years ago

If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term

Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

d = $a_{2}$ - $a_{1}$ = $a_{3}$ - $a_{2}$

Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

$a_{n}$ = $a_{1}$ + (n - 1)d

$a_{1}$ = 2k = 2 × 2 = 4 and

d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5

Hence

$a_{8}$ = 4 + (7 × 5) = 4 + 35 = 39

4 0

3 years ago