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aksik [14]
3 years ago
14

Solve the system​ graphically, and indicate whether each solution region is bounded or unbounded. Find the coordinates of each c

orner point.
Use the graphing tool to graph the system of inequalities. Graph the region that represents the correct solution only once.

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

Answer:

Attached below

Step-by-step explanation:

Coordinates of end points are;

(2,11)

(6.6,8.7)

(9,4)

Each solution region is unbounded.

The final solution region is bonded.

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Please help me guys
Dima020 [189]
Hello!

OC = OD = Radius
6x + 2 = 10x - 16
6x - 10x = -16 - 2
-4x = -18
x = -18/-4
x = 4.5

Radius = OC = 6(4.5) + 2 = 29 units
5 0
3 years ago
Read 2 more answers
8s+4(4s-3)=4(6s+4)-4​
elena55 [62]

Answer:

There is no solution.

5 0
3 years ago
Judy took $30 with her to spend on popcorn and drinks for herself and her friends at the movie theater. The price for each bag o
navik [9.2K]
30-8=22 but I’m not sure about the graph part
3 0
3 years ago
What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
2 years ago
37 is what percent of 148? I also need 148 is what percent of 37? Thank you!
yuradex [85]

Answer:

25%

400%

Step-by-step explanation:

37=148x

x=0.25

25%

148=37x

x=4

5 0
2 years ago
Read 2 more answers
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