Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
16
Step-by-step explanation:
Hope you get it.
You would just convert 5 1/3 into a improper fraction 16/3=16/3
Answer:
45x + 180 = - 720
Step-by-step explanation:
Let the required number be x.
Therefore, product of 45 and x = 45x
180 added to 45x = 45x + 180
Since, 180 Added to the product of 45 and a number totals negative 720.
So, 45x + 180 = - 720
C is the answer i thinkkk