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2 years ago

6

PLEASE HELP . ILL MAKE BRAINLIEST !! PLEASE

1 answer:

asambeis [7]2 years ago

8 0

Answer:

62

Step-by-step explanation:

add

and then mutupy them together

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ASAP! I’ll give u Brainly !

kondor19780726 [428]

Answer:

I'm sorry but if your struggling with this iďk what to tell you chief

Its (1,5)

7 0

2 years ago

Read 2 more answers

An accident at an oil drilling platform is causing a circular oil slick. The slick is 0.07 foot thick, and when the radius of th

ololo11 [35]

Answer: $43.54 ft^3/min$

Step-by-step explanation:

Given

Thickness of oil slick=0.07 foot

radius of slick=110 ft

$\frac{\mathrm{d} r}{\mathrm{d} t}=0.9 ft/s$

Let V be the volume of oil slick

so, $V=0.07\pi \cdot r^2$

rate of oil flowing is

$\frac{\mathrm{d} V}{\mathrm{d} t}=0.07\times 2\pi \cdot r\frac{\mathrm{d} r}{\mathrm{d} t}$

$\frac{\mathrm{d} V}{\mathrm{d} t}=0.07\times 2\pi \times 110\times 0.9=43.54 ft^3/min$

7 0

2 years ago

Factoring quadratic with a common factor Factor completely 2x^2-18x+36

rodikova [14]

Answer:

$2 {x}^{2} - 18x + 36 \\ 2 {x}^{2} - 12x - 6x + 36 \\ 2 x(x - 6) - 6(x - 6) \\ (2x - 6)(x - 6)$

6 0

2 years ago

Simplify the problem: Sin theta Sec Theta

kherson [118]

Answer:

$\tan \theta$

Step-by-step explanation:

We have to simplify the following expression as given by

$\sin \theta \times \sec \theta$

= $\frac{\sin \theta}{\cos \theta}$

= $\tan \theta$ ( Answer )

Because, we know that $\sec \theta =\frac{1}{\cos \theta}$ and $\tan \theta = \frac{\sin \theta}{\cos \theta}$

If we consider $\sin \theta = \frac{Perpendicular}{Hypotenuse}$ and $\sec \theta = \frac{Hypotenuse}{Base}$ ,

then $\sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta$

3 0

2 years ago

The vertex of the parabola below is at the point (3,2) and the point (4,6) is on the parabola. What is the equation of the parab

nata0808 [166]

Answer:

$\large\boxed{y=4(x-3)^2+2\ \bold{vertex\ form}}\\\boxed{y=4x^2-24x+38\ \bold{standard\ form}}$

Step-by-step explanation:

The vertex form of a parabola:

$y=a(x-h)^2+k$

(h, k) - vertex

We have the vertex at (3, 2) → h = 3 and k = 2.

Substitute:

$y=a(x-3)^2+2$

The point (4, 6) is on athe parabola. Put the coordinates of this point to the equation:

$6=a(4-3)^2+2$ <em>subtract 2 from both sides</em>

$6-2=a(1)^2+2-2$

$4=a\to a=4$

Finally:

$y=4(x-3)^2+2$ <em>vertex form</em>

<em>use (a - b)² = a² - 2ab + b²</em>

$y=4(x^2-6x+9)+2$ <em>use the distributive property</em>

$y=4x^2-24x+36+2$

$y=4x^2-24x+38$ <em>standard form</em>

6 0

2 years ago