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Troyanec [42]
3 years ago
10

Write an expression for the sequence of operations described below.

Mathematics
1 answer:
Natalka [10]3 years ago
4 0

u( t - 2s)

double s is expressed as 2s

subtract this result from t gives t - 2s

multiply this result by u gives u × (t - 2s) = u( t - 2s)


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Boxes 1 and 4 apply :)
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The Width of a rectangle is 2w+3. The length is equal to 4 times its width. Write an expression to represent the perimeter of th
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Since the perimeter is the sum of the length of all sides we multiply width and length by 2 and then add them together

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xenn [34]

This question is not correctly written

Complete Question

The Henderson Hawks minor-league baseball team is giving away baseballs an

game. The balls cost $3 each and the towels cost $2 each. The team wants to give away 200 items and have 500 to spend. How many of each item should the team give away Show your

work or explain your reasoning.

Answer:

They should give away 100 balls and 100 towels

Step-by-step explanation:

Let the number of balls = x

Let the number of towels = y

x + y = 200........ Equation 1

y = 200 - x

$3 × x + $2 × y = $5000

3x + 2y = 5000...... Equation 2

3x + 2(200 - x)= 5000

3x + 400 - 2x = 5000

Collect like terms

3x - 2x = 500 - 400

x = 100

Number of balls to be given away = 100

Note:

y = 200 - x

y = 200 - 100

y = 100

Number of towels to be given away = 100

Therefore, they should give away 100 balls and 100 towels

3 0
3 years ago
Write the product form of 3 a² b ³<br>​
kifflom [539]

Answer:

a³-b³= (a-b)(a²+ab+ b²)

Step-by-step explanation:

3 0
3 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0
3 years ago
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