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Troyanec [42]
3 years ago
10

Write an expression for the sequence of operations described below.

Mathematics
1 answer:
Natalka [10]3 years ago
4 0

u( t - 2s)

double s is expressed as 2s

subtract this result from t gives t - 2s

multiply this result by u gives u × (t - 2s) = u( t - 2s)


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What is the value of y?
Olegator [25]

Answtgdyb4r

yjyjytjyjyu

Step-by-step explanation:

htbr5tbjbtrhyhtrh

7 0
3 years ago
Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th
trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

    t = 20: 999 fishes

    t = 30: 1168 fishes

(c)

P(\infty) = 1200

Step-by-step explanation:

Given

P(t) =\frac{d}{1+ke^-{ct}}

d = 1200\\k = 11\\c=0.2

Solving (a): Fishes at t = 0

This gives:

P(0) =\frac{1200}{1+11*e^-{0.2*0}}

P(0) =\frac{1200}{1+11*e^-{0}}

P(0) =\frac{1200}{1+11*1}

P(0) =\frac{1200}{1+11}

P(0) =\frac{1200}{12}

P(0) = 100

Solving (a): Fishes at t = 10, 20, 30

t = 10

P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483

t = 20

P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999

t = 30

P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168

Solving (c): \lim_{t \to \infty} P(t)

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of e^{-ct} decreases

This implies that:

{t \to \infty} = {e^{-ct} \to 0}

So:

The value of P(t) for large values is:

P(\infty) = \frac{1200}{1 + 11 * 0}

P(\infty) = \frac{1200}{1 + 0}

P(\infty) = \frac{1200}{1}

P(\infty) = 1200

5 0
3 years ago
The point R is located at (-5, -5). After translation, R' is the point (-3, -2). What is the translation rule?
Dominik [7]

Answer:

Option 1

Step-by-step explanation:

(-5 + 2, -5 + 3) = (-3, -2)

7 0
3 years ago
What is the complete factorization of the polynomial below?
Hunter-Best [27]

The complete factorisation of the polynomial given; x³ + 2x² + 4x + 8 as in the task content can be factorised and determined as; Choice D; (x+2)(x+2i)(x-2i).

<h3>What is the complete factorisation of the given polynomial; x³ + 2x² + 4x+8?</h3>

It follows from the given task content that the polynomial whose factors are to be determined by means of factorisation is; x³ + 2x² + 4x+8.

It follows from observation that one of the zeros of the polynomial expression is at; x = -2.

Consequently, one of the factors of the polynomial in discuss is; (x+2).

x³ + 2x² + 4x+8 = (x+2) (x² - 4i²)

= (x+2)(x+2i)(x-2i)

Consequently, it follows that the complete factorisation of the polynomial is; (x+2)(x+2i)(x-2i).

Read more on polynomial factorisation;

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8 0
2 years ago
#19 how do you do the work???!
Semenov [28]

Answer:

x=\frac{1}{3}

Step-by-step explanation:

move the terms with x to the left side of the equation:

add 3x to both sides

3x-1+3x=1

add 3x and 3x

6x-1=1

move all term not containing x to the right side:

add 1 to both sides of the equation

6x=1+1

6x=2

divide each term by 6

\frac{6x}{6}=\frac{2}{6}

x=\frac{2}{6}

simplify the fraction

x=\frac{1}{3}

8 0
3 years ago
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