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Greeley [361]
4 years ago
10

Find all possible values for θ if 0° < θ < 360° and tanθ = -1.

Mathematics
1 answer:
MAVERICK [17]4 years ago
7 0
When tan theta = 1  theta = 45 degrees in the first quadrant.

When  its = -1  one value of theta is -45 degrees.

Also as the tangent is negative in the second quadrant theta can also be 135 degrees or - 225 degrees. 
in fourth quadrant  we have 315 degrees.
Its not  225 degrees because the tangent is positive in 3rd quadrant.

Correct answer is  a, b, c and e.
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Solve st + 3t = 6 for s
vaieri [72.5K]

st + 3t = 6 for s

Subtract 3t to both sides

st + 3t  - 3t = 6 - 3t

Simplify

st = 6 - 3t

Divide both sides by t

st/t = (6-3t)/3

simplify

s = 6/3 - 3t/3

s = 2 - t


6 0
3 years ago
Explain how you can use base ten blocks to find 1.54+ 2.37
solong [7]
0.00

*First column to your left - ones column (1)
*Column just after decimal place, in the middle - tenths column (1/10)
*Column to the far right - hundredths column (1/100)

The only numbers that can go in these columns are 0-9.

-------------

1.54 + 2.37 

= (1 + 5/10 + 4/100) + (2 + 3/10 + 7/100)

= 1 + 5/10 + 4/100 + 2 + 3/10 + 7/100

= 3 + 8/10 + 11/100

= 3 + 8/10 + (10/100 + 1/100)

= 3 + 8/10 + (1/10 + 1/100)

= 3 + 8/10 + 1/10 + 1/100

= 3 + 9/10 + 1/100

= 3.91
6 0
3 years ago
Budget
Leno4ka [110]
My guess would be A ! Hope this helps
5 0
3 years ago
Ribbon is sold by the foot. If Heather is making 84 bows, ​how many feet​ of ribbon must she buy?
Anuta_ua [19.1K]

Answer:

84 feet of ribbon is needed

Step-by-step explanation:

Given : Ribbon is sold by the foot. If Heather is making 84 bows, ​how many feet​ of ribbon must she buy?

Explanation :  If ribbon is sold by the foot, then if Heather is making 84 bows, then Heather would need 84 feet

To put in simple terms - 1 bow needs 1 foot of ribbon

7 0
3 years ago
Write an expression in factored form that is equivalent to the given expression. 1/2x + 4 . can u also tell how you solved it ?
Rufina [12.5K]
2 ways: Easy and hard
Hard=A
Easy=B
A: 1/2x+4 work from there so we do fun stuff with it make something that can be simplified so 1/2x+4 times (2/2)=x+8 now square the whole thing and put the result in a square root thingie (x+8)^2=x^2+16x+64 \sqrt{x^2+16x+64} multiply the whole thing by 4/4 and put \sqrt{16} [\tex] on top so then &#10;[tex] \sqrt{x^2+16x+64} times \frac{ \sqrt{16} }{4}=\frac{\sqrt{(16)(x^2+16x+64)}}{4}=\frac{ \sqrt{16x^2+256x+1024} }{4} to solve it, factor out the 16 in the square root and then square root 16 to get 4 then it will be (4 times square root of equation)/4=square root of equatio factor square root of equation and square root it and get x+8 divide by 2 to get 1/2x+4


B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve

5 0
3 years ago
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