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3 years ago

15

I need help on 1 and 2 please will give brainliest

1 answer:

MatroZZZ [7]3 years ago

4 0

1) Amount: 8.26 milliliters (ml) of mercury volume
Equals: 111.79 grams (g) in mercury mass
Calculate grams of mercury per 8.26 milliliters unit.

B) volume = mass / density
volume = 120 g / 13.6 = 8.82 ml

2) (1.2 L) x (1000 mL/L) x (0.74 g/mL) = 888 g

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1. What is the density, in g/cm², of a substance weighing 22.2 cg with dimensions of 0.333

RUDIKE [14]

Mass=22.2cg=2.22g

Volume:-

$\\ \tt\longmapsto 0.333(0.444)(0.555)=0.08cm^3$

So

$\\ \tt\longmapsto Density=\dfrac{Mass}{Volume}$

$\\ \tt\longmapsto Density=\dfrac{2.22}{0.08}=27.75g/cm^3$

7 0

2 years ago

Carmen has a sample of matter. It is clear and smells sour. The sample is also thick but it flows when poured. Which is the best

Oksanka [162]

Answer:

it's a liquid because it flows

Explanation:

solids don't flow and rocks can be clear too like quartz

6 0

4 years ago

Read 2 more answers

A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.

Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

$[SCN^-]=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=0.063 mol/L$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

1) Moles of sodium thiocyanate = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = $4.8\times 10^{-4} M$

$n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol$

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in $2.4\times 10^{-6}mol$ of NaSCN.

$=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol$

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

$n'=0.002 M\times 0.21 L=0.00042 mol$

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

$3\times 0.00042 mol=0.00126 mol$

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

$[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L$

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME<br> a)<br> b)<br> c)<br> or d)?

PilotLPTM [1.2K]

Answer:

D / 15.0 g

Explanation:

3 % volume thus shows that there are 3 g of an solute in every 100mL of solutions

.. there will be 3 × 5000÷ 100 of H2O2 in a 500 mL bottle

5 0

3 years ago

On a topographic map every fifth contour is darkened. What is this line call?

Veronika [31]

I think it is D but im not sure

8 0

4 years ago