Answer:
A = 65.46 u
Explanation:
Given that,
The composition of zinc is as follows :
Zn-64 = 48.63%
Zn-66 = 27.90%
Zn-67 = 4.10%
Zn-68 = 18.75%
Zn-70 = .62%
We need to find the average atomic mass of the given element. It can be solved as follows :

So, the average atomic mass of zinc is 65.46 u.
Answer:
There are 63.546 grams in a 2.50 moles of copper.
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Explanation:
General electronic configuration for the given groups are as follows.
For 4A(14) : 
This means that there are 4 unpaired electrons in group 4A(14).
For 7A(17) :
So, there are 7 unpaired electrons present in group 7A(17).
For 1A(1) : 
Hence, there is only one unpaired electron present in group 1A(1).
For 6A(16) :
So, there are 6 unpaired electrons present in group 6A(16).