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likoan [24]
2 years ago
10

1. What is the density, in g/cm², of a substance weighing 22.2 cg with dimensions of 0.333

Chemistry
1 answer:
RUDIKE [14]2 years ago
7 0
  • Mass=22.2cg=2.22g

Volume:-

\\ \tt\longmapsto 0.333(0.444)(0.555)=0.08cm^3

So

\\ \tt\longmapsto Density=\dfrac{Mass}{Volume}

\\ \tt\longmapsto Density=\dfrac{2.22}{0.08}=27.75g/cm^3

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When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h
Pavel [41]
NH₃:

N = 8*10²²
NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²
NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃                   <span>+                        3O</span>₂                      ⇒<span>          2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol                     :                        3mol                   :             2mol
0.133mol             :                        0.116mol           :             0,0665mol
limiting reactant

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n = 0.0665mol
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6 0
3 years ago
HELP ASAP PLZ!!!! Find the mass of each substance. Show your work.
Gemiola [76]

Answer:

A. m C5H12 = 108.23 g

B. m F2 = 547.142 g

C. m Ca(CN)2 = 71.85 g

Explanation:

  • mass (m) = mol (n) × molecular weigth (Mw)

∴ Mw C5H12 = ((12.011)(5)) + ((1.008)(12)) = 72.151 g/mol C5H12

∴ Mw F2 = (18.998)(2) = 37.996 g/mol F2

∴ Mw = Ca(CN)2 = 40.078+((12.011+14.007)(2)) = 92.114 g/mol Ca(CN)2

A. m C5H12 = ( 1.50 mol)×(72.151 g/mol) = 108.23 g C5H12

B. m F2 = (14.4 mol)×(37.996 g/mol) = 547.142 g F2

C. m Ca(CN)2 = (0.780 mol)×(92.114 g/mol) = 71.85 g Ca(CN)2

8 0
3 years ago
If a car can go from 0 to 60 mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50
tangare [24]

Answer:

87.5 mi/hr

Explanation:

Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.

vf = 60 mi/hr

vi = 0 mi/hr

Δt = 8 secs

a = vf - vi/ Δt

= 60 mi/hr - 0 mi/hr/ 8 secs

= 60 mi/hr / 8 secs

= 7.5 mi/hr^2

Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.

vi = 50 mi/ hr

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a = 7.5 mi/ hr^2

a = vf - vi/ Δt

7.5 = vf - 50 mi/hr / 5 secs

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87.5 mi/ hr = vf

7 0
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Shtirlitz [24]

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Hope that was helpful.Thank you!!!

8 0
3 years ago
How much percent of earth is water
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