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vivado [14]
3 years ago
12

The chemical reaction in which solid calcium oxide is treated liquid water is an example of what: A) decomposition B)combustion

reaction C)single replacement D)synthesis E)double replacement
Chemistry
1 answer:
laiz [17]3 years ago
8 0

Answer:

The chemical reaction in which solid calcium oxide is treated liquid water is an example of Synthesis reaction. Hence, the answer is (D) Synthesis.

Explanation:

The formula of Calcium Oxide is CaO.

The formula of liquid water is H₂O.

Calcium Oxide reacts with water and forms Calcium Hydroxide. The Chemical equation is shown below.

CaO + H₂O --> Ca(OH)₂.

This is a Synthesis reaction because Ca(OH)₂ is synthesized by using Calcium Oxide and water.

The product of this reaction is calcium hydroxide, also known as slaked lime.

Thus, when calcium oxide reacts with water, slaked lime is produced.  

Calcium oxide is also known as lime and is most commonly used for many purposes. It can be used for pH correction of water or for its disinfection (with excess lime).

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A 25.0 ml sample of 0.150 m hydrazoic acid is titrated with a 0.150 m naoh solution. what is the ph after 15.0 ml of the sodium
babunello [35]
First, we need to calculate moles of hydrazoic acid NH3:

moles NH3 = molarity * volume 

                    = 0.15 m * 0.025 L

                   =  0.00375 moles

moles NaOH = molarity * volume 

                       = 0.15 m * 0.015 L

                       = 0.00225 moles 

after that we shoul get the total volume = 0.025L + 0.015L

                                                                   = 0.04 L

So we can get the concentration of NH3 & NaOH by:

∴[NH3] = moles NH3 / total volume 

           = 0.00375 moles / 0.04 L

           = 0.09375 M

∴[NaOH] = moles NaOH / total volume 

                = 0.00225 moles / 0.04 L

                = 0.05625 M

then, when we have the value of Ka of NH3 so we can get the Pka value from:

Pka = -㏒Ka 

       = - ㏒ 1.9 x10^-5

      = 4.7 

finally, by using H-H equation we can get PH:

PH = Pka + ㏒[salt/ basic]

PH = 4.7 +㏒[0.05625/0.09375]

∴ PH = 4.48 


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