cody has a box of cereal. on monday he ate 1/7 of the cereal. on tuesday, he ate 1/6 of the remaining cereal. what fraction of t
1 answer:
So, on Monday he ate 1/7, that means from a whole 7/7, take away 1/7, the leftover was 6/7 then.
on Tuesday, he ate 1/6 of the leftover, namely, 1/6 of 6/7.
now, how much is 1/6 of 6/7? well, is just their product,
now, so he really ate 1/7 of the whole thing on Tuesday, there were 6/7 remaining, how much is 6/7 - 1/7? yeap, you guessed it, 5/7.
on Tuesday, he ate 1/6 of the leftover, namely, 1/6 of 6/7.
now, how much is 1/6 of 6/7? well, is just their product,
now, so he really ate 1/7 of the whole thing on Tuesday, there were 6/7 remaining, how much is 6/7 - 1/7? yeap, you guessed it, 5/7.
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Both the numerator and denominator approach 0, so this is a candidate for applying L'Hopital's rule. Doing so gives
This again gives an indeterminate form 0/0, but no need to use L'Hopital's rule again just yet. Split up the limit as
Now recall two well-known limits:
Compute each remaining limit:
So, the original limit has a value of
2/3 + 2/3 + 1/3 + 1/3 - 0 = 2
Answer:
Option D is correct.
Step-by-step explanation:
Let V be the volume of hay in each stack
Given:
Length of the each stack is
And Jay stores hay in cubic stacks on his farm.
The volume of the cone is.
Now, we substitute value of length of stack in above equation.
Therefore, the volume of hay in each stack is