Answer:
Answer is D
Step-by-step explanation:
I took the test and it is right because there are 2 chunks of dots in two spots
Answer: 0=0
Step-by-step explanation:
First you want to solve for x
2x+y=−4
Step 1: Add -y to both sides.
2x + y + −y =−4+ −y
2x=−y−4
Step 2: Divide both sides by 2.
2x/2= -y-4/2
x=-1/2y-2
Then you want to plug in your answer for x into the equation so:
2(-1/2y-2)+y=-4
Step 1: Simplify both sides of the equation.
2(-1/2y-2)+y=-4
(2)(
−1/
2
y)+(2)(−2)+y(Distribute)
−y+−4+y=−4
(−y+y)+(−4)=−4(Combine Like Terms)
−4=−4
−4=−4
Step 2: Add 4 to both sides.
−4+4=−4+4
0=0.
Sorry if this wasn't the answer your looking for. If you need more help I suggest using Ma.th.Pa.pa calculator but with out the periods. Hope you have a good day :)
Answer:
5
Step-by-step explanation:
use the distributive property
6 * 1/2 = 3
6 * 1/3 = 2
3 + 2 = 5
<em><u>Hope this helped! Have a nice rest of ur day! Plz mark as brainliest!!!</u></em>
<em><u>-Lil G</u></em>
<h3>
Answer: Triangular prism</h3>
If you folded the figure up, you would have a prism where the parallel bases are right triangles. Each lateral face is a rectangle.
It might help to imagine a room where the floor and ceiling are triangles (they are identical or congruent triangles). Each wall of this room is one of the rectangles shown.
Answer:
The lines representing these equations intercept at the point (-4,2) on the plane.
Step-by-step explanation:
When we want to find were both lines intercept, we are trying to find a pair of values (x,y) that belongs to both equations, which means that it satisfies both equations at the same time.
Therefore, we can use the second equation that gives us the value of y in terms of x, to substitute for y in the first equation. Then we end up with an equation with a unique unknown, for which we can solve:
Next we use this value we obtained for x (-4) in the same equation we use for substitution in order to find which y value corresponds to this:
Then we have the pair (x,y) that satisfies both equations (-4,2), which is therefore the point on the plane where both lines intercept.
