Answer: THe answer is C for number 1.
The answer is A for number 2
Explanation:
If after gram-staining a pure bacterial culture red and purple cocci are observed and the adjacent cells were not of the same colour, It means it's an old stock of culture.
The Gram stain process is a multi-step differential staining procedure. Differential staining separates organisms based on how they respond to various stains. To put it another way, two organisms in a sample that has been stained differently might appear to be different colours.
Gram-positive and Gram-negative are the two primary subtypes of bacteria. Based on how these bacteria respond to the Gram stain, several types are identified. The hue of a Gram stain is purple. The bacteria in a sample will either stay purple or change pink or red when the stain and bacteria interact.
The bacteria are Gram-positive if they continue to be purple.
The bacteria are Gram-negative if they turn pink or crimson.
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Answer:
population = 600
heterozygotes = 2pq
The homozygous recessive percentage = 
q = 0.1
Solve for q:
∴ q = 
∴ q = 
∴ q = 0.316
solve for p:
for p + q = 1,
thus p = 1 – q = 1 – 0.316 = 0.684
The heterozygotes = 2pq
2pq = 2 x 0.316 x 0.684 = 0.432
600 x 0.432 = 259.2 = 259
so, the population reaches Hardy Weinberg equilibrium, 259 of indviduals should be heterozygous for this trait.
Hence, the correct answer is 259
.
Answer:c. small intestine
Explanation:in humans, digestion is extracellular.specific parts of the digestive system has specific functions.digestion involves the mechanical breakdown and chemical breakdown of food.
These chemicals called enzymes requires specific conditions to be effective.the salivary glands found in the mouth is the first enzyme that food encounters in the digestive system.this gland produces amylase which acts starch.
The stomach mixes food mechanically with enzymes such as the gastric juice containing pepsin.
Digestion initiated in the stomach continues in the intestine,here pancreatic juice from the pancreas and bile from the liver acts on ingested food.
Answer: slow; late; low; vegetative
Explanation: Due to the casting of deep shade on the forest understory by eastern hemlock, direct sunlight and other necessities for photosynthesis and other life processes needed by the herbaceous plant species for optimum growth is being deprived.
However, coupled with the nature of these herbaceous plant species, having non-woody stems with their growth above the ground level often dieing off particularly in winter in the temperate zone, makes their growth in that kind of location to be stunted.
Thus, herbaceous plant species with slow growth rate leading to late sexual maturuty while having low expanded energy on seeds due to low photosynthetic rate and low vegetative reproduction should be expected.