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F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
I think its D
Step-by-step explanation:
Sorry if its wrong
Answer: 60%
Step-by-step explanation:
Since, According to the question, Last quarter, we successfully completed an average of about 5 chemical analyses per day.
Therefore initially our average = 5 chemical analyses per day.
Again, From the question, This quarter, we have increased this average to about 8 per day.
Therefore New average =chemical analyses 8 per day
Thus, Percentage change in the average = (Initial average - New average)×100/ initial average
= 
= 
= 60 %
Therefore, Percentage change in the average=60 %
Answer:
13 pears in the 21st bag
Step-by-step explanation:
mean = total number of pears/total number of bags
8 = x/21
x = 168
number of pears in 20 bags = (6 x 2) + (7 x 6) + (8 x 9) + (9 x 1) + (10 x 2)
= 155
number of pears in the 21st bag = 168 - 155
= 13
