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lilavasa [31]
3 years ago
10

The angle of elevation from a soccer ball on the ground to the ground to the top of the goal 34 degrees. If the goal is 8 ft tal

l, what is the distance from the ball to the goal. Draw a picture, and then solve the missing part

Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0
Check the picture below.

make sure your calculator is in Degree mode.

jolli1 [7]3 years ago
6 0

Answer:

11.86\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

In the right triangle ABC  

tan(34\°)=\frac{BC}{AB}

substitute the values and solve for AB

tan(34\°)=\frac{8}{AB}

AB=\frac{8}{tan(34\°)}=11.86\ ft

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How much less than 3x^2−7x+9 is 2x^2+4x−8 ?<br> Thanks!!
maks197457 [2]
Simplify.
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1. 3x^2-2x^2 = x
2. -7x + 4x = -3x
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Thus, 2x^2+4x−8 is x -3x +1 less than 3x^2−7x+9
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(08.02)Which of the following graphs best represents the solution to the pair of equations below?
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2 years ago
Geometry math question no Guessing and Please show work thank you
Fiesta28 [93]

Theorem

In a triangle, the measure of an exterior angle equals the sum of the measures of its two remote interior angles.

x + y = z

4n - 18 + n + 8 = 133 - 6n

5n - 10 = 133 - 6n

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3 0
3 years ago
Read 2 more answers
2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diver
timofeeve [1]

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

y = 2x^{2} - 9x - 56

2x^{2} - 9x - 56 = 0

So

a = 2, b = -9, c = -56

Then

\bigtriangleup = b^{2} - 4ac = (-9)^{2} - 4*2(-56) = 529

x_{1} = \frac{-(-9) + \sqrt{529}}{2*2} = 8

x_{2} = \frac{-(-9) - \sqrt{529}}{2*2} = -3.5

It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

7 0
3 years ago
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