Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
Number 3 is the correct answer
If the mean is 32 and there is 4 numbers
then the numbers add to 32x4 which is 128
128-15-21-75=17
fourth number is 17
Answer:
x = -7, x = 7
Step-by-step explanation:
Firstly, you are going to set the equation to 0, and then factor it.
Set equation to 0 -----> f(x)= x^2 - 49 will become x^2 - 49 = 0
Now, you're going to factor the equation.
You'll get (x-7) (x+7) upon factoring.
Thirdly, you will set (x-7)(x+7) equal to 0 and also solve for x.
Keep in mind that you'll be treating them as two separate equations
So, ----> (x-7) = 0 (x+7) = 0
When you solve for the x, you'll find out that x is equal to 7 and -7 ---> these are your zeros.
