What is the radius of a circle whose equation is (x + 5)2 + (y - 3)2 = 42?

Mathematics

2 answers:

777dan777 [17]3 years ago

8 0

Answer:

x=−y+19

Step-by-step explanation:

(x+5)(2)+(y−3)(2)=42

Step 1: Add -2y to both sides.

2x+2y+4+−2y=42+−2y

2x+4=−2y+42

Step 2: Add -4 to both sides.

2x+4+−4=−2y+42+−4

2x=−2y+38

Step 3: Divide both sides by 2.

−2y+38

x=−y+19

Arlecino [84]3 years ago

3 0

Divide the numbers I did this I got a check

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SCORPION-xisa [38]

First, multiply 1,127 & 1 by 2
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2,254 cups & 2 fl. ounces

4 0

3 years ago

What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

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$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$