Answer:
She spent 2 and a half hours doing extra work.
1) Line should be parallel to y = 3x+6, so slope of this line should be =3.
y=mx +b
y=3x +b
Now we have to find b (y-intercept), using the point (-10, 2.5).
2.5 = 3*(-10)+b
b=2.5+30=32.5
y=3x + 32.5
2) The line should be perpendicular to y = -4x -2, so its slope is going to be negative reciprocal m= 1/4.
Now we have to find b (y-intercept), using the point (-16, -11).
y=(1/4)x +b
-11=(1/4)*(-16) + b
-11 = -4 +b
b = -7
y=(1/4)x - 7
Answer: Choice A
y = -3(x+2)^2 + 10
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Work Shown:
y = -3x^2-12x-2 is in the form y = ax^2+bx+c with
a = -3
b = -12
c = -2
The x coordinate of the vertex is
h = -b/(2a)
h = -(-12)/(2*(-3))
h = 12/(-6)
h = -2
We'll plug this into the original equation to find the corresponding y coordinate of the vertex.
y = -3x^2-12x-2
y = -3(-2)^2-12(-2)-2
y = 10
So k = 10 is the y coordinate of the vertex.
Overall, the vertex is (h,k) = (-2,10)
Meaning that we go from this general vertex form
y = a(x-h)^2 + k
to this
y = -3(x - (-2))^2 + 10
y = -3(x+2)^2 + 10
Answer:
−3x+4
Step-by-step explanation:
