The height of a box is 3 inches. The length is three inches more than the width. Find the width if the volume is 390. Select one
: A. 13 in. B. 130 in. C. 10 in. D. 3 in.
1 answer:
Let
x---------> the length side of the box
y---------> the width side of the box
we know that
h=3 in
V=390 in³
volume of the box=x*y*3-------> 390=x*y*3-----> x*y=130------> equation 1
x=3+y------> equation 2
substitute 2 in 1
[3+y]*y=130-----> y²+3y=130------> y²+3y-130=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
y=10 in
x=3+y-----> x=3+10-----> x=13 in
the answer is
the width is 10 in
x---------> the length side of the box
y---------> the width side of the box
we know that
h=3 in
V=390 in³
volume of the box=x*y*3-------> 390=x*y*3-----> x*y=130------> equation 1
x=3+y------> equation 2
substitute 2 in 1
[3+y]*y=130-----> y²+3y=130------> y²+3y-130=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
y=10 in
x=3+y-----> x=3+10-----> x=13 in
the answer is
the width is 10 in
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2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Step-by-step explanation:
<u>1. 5 in and 1/3 in</u>
Here,
<u>2. 5 in and 4/3 in</u>
Here,
<u>3. 5/2 in and 4/3 in</u>
<u>4. 7/6 in and 6/7 in</u>
<u>Let</u>
<u>Hence,</u>
1. 5 in and 1/3 in: Area = 5/3 in^2
2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Keywords: Rectangle, Area
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