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Sladkaya [172]
4 years ago
13

Determine the intervals on which the function is increasing, decreasing, and constant.

Mathematics
2 answers:
Salsk061 [2.6K]4 years ago
7 0
A is your answer I think hope I helped
aliina [53]4 years ago
5 0

Answer:

b. Increasing x > 0; Decreasing x < 0

Step-by-step explanation:

We have been given graph of a function. We are asked to find the intervals on which our function is increasing and decreasing.

We know that when graph of function is going upwards from left to right then the graph is increasing.

When graph of function is going downwards from left to right then the graph is decreasing.

Upon looking at our given graph, we can see that for x values less than 0, the graph is going downwards from left to right, therefore, our function is decreasing on interval x.

We can see from our given graph that for x values greater than 0, the graph is going upwards from left to right, therefore, our function is increasing on interval x>0.

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In a volley ball game, Steve served the ball over the net 17 out of 25 times. What percent did he not make over the net?
kkurt [141]

Answer:

32%

Step-by-step explanation:

25 - 17 = 8

8/25 x 100% = 32%

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4 years ago
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Miguel runs 6 miles in 55 minutes. At the same rate, how many miles would he run in 44 minutes
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You can write this in a proportion way: 6/55 = x/44.
Multiply both sides by 11 to get rid of the 55 and 44: 6/5 = x/4
Now, multiply both sides by 20: 5x = 24. x = 4.8

Therefore, he can run 4.8 miles in 44 minutes.
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alexgriva [62]

Answer:

For number 13, I think it is rational, integer, and whole number

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3 years ago
I need help ASAP this is due today
hjlf
45 degree angle from (0,0)
5 0
3 years ago
Jake has made a scale drawing of a sand pit he
SVEN [57.7K]

Answer: The scale is 5cm/m  (5 cm in the drawing are equivalent to 1 meter on the actual pit)

Step-by-step explanation:

When we have an original measure M, and we redraw it with a new scale, where the new measure is m, the scale used is equal to:

scale = m/M.

In this case, we know that:

The pit is 3m, by 5m

and the drawing to scale is 15cm by 25cm

(15cm is the rescaled version of the 3m side, and 25cm is the rescaled version of the 5m side)

Using the equation above, we can find that the scale is:

Scale = 15cm/3m = 5cm/m

and, if we use the other side, we get:

Scale = 25cm/5m = 5cm/m

Both calculations give the same scale, as expected.

Then the scale is 5cm/m, which means that 5 centimeters in the drawing are equivalent to one meter in the real pit.

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