1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sladkaya [172]
3 years ago
13

Determine the intervals on which the function is increasing, decreasing, and constant.

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
A is your answer I think hope I helped
aliina [53]3 years ago
5 0

Answer:

b. Increasing x > 0; Decreasing x < 0

Step-by-step explanation:

We have been given graph of a function. We are asked to find the intervals on which our function is increasing and decreasing.

We know that when graph of function is going upwards from left to right then the graph is increasing.

When graph of function is going downwards from left to right then the graph is decreasing.

Upon looking at our given graph, we can see that for x values less than 0, the graph is going downwards from left to right, therefore, our function is decreasing on interval x.

We can see from our given graph that for x values greater than 0, the graph is going upwards from left to right, therefore, our function is increasing on interval x>0.

You might be interested in
Leo wants to paint a mural that covers a wall with an area of 600 square feet. The height of the wall is 2/3 of its length. What
Gre4nikov [31]

Answer: attached

Step-by-step explanation:

4 0
3 years ago
PLS ANSWER AS SOON AS POSSIBLE
telo118 [61]
Side angle side and yes
8 0
2 years ago
3x+2=5x What is the answer for this solving equations with variables on each side
Yanka [14]
3x +2= 5x
-3x
2= 2x
/2
1= x
So first I got all the x’s on one side and the whole numbers on the other side. So we had 2 on one side and 2x on the other. From there we divided by the number of x’s which was 2 so we can get one x only. So 2/2= 1 so x =1
6 0
3 years ago
Read 2 more answers
Branden and Pete both play running back. Branden carries the ball 75 times for 550 yards and Pete had 42 carries for 380 yards w
mars1129 [50]

Answer:

Pete runs farther per carry.

Step-by-step explanation:

Given:

Branden and Pete both play running back.

Branden carries the ball 75 times for 550 yards.

Pete had 42 carries for 380 yards

Question asked:

Who runs farther per carry ?

Solution:

First of all we find each boy's distance covered per carry:-

<u>For Branden</u>

Branden carries the ball 75 times for = 550 yards.

Branden carries the ball 1 time for = \frac{550}{75} =7.34\ yard

<u>For Pete </u>

Pete carries 42 times for = 380 yards

Pete carries 1 time for = \frac{380}{42} =9.05\ yards

As Pete runs 9.05 yards for 1 carry while Branden runs 7.34 yards for 1 carry, hence Pete runs farther per carry.

3 0
3 years ago
Anyone knows the answer
murzikaleks [220]

Answer:C

Step-by-step explanation:

3.1 x 10^(-4) x 8.5 x 10^(-2)

3.1 x 8.5 x 10^(-4) x 10^(-2)

26.35 x 10^(-4-2)

26.35 x 10^(-6)

2.635 x 10^1 x 10^(-6)

2.635 x 10^(1-6)

2.635 x 10^(-5)

3 0
4 years ago
Other questions:
  • Many income tax systems are calculated using a tiered method. Under certain tax law, the first $100 000 of earning are subject t
    11·1 answer
  • Determine the slope and y-intercept of the line y=-6x+8
    12·2 answers
  • What is the value of n?
    12·2 answers
  • Which number is NOT in the solution set of the inequality x &gt; −15?
    8·2 answers
  • What do you call a fraction in which the only common factor of the numerator and denominator is 1? A) complex form B) compound f
    12·1 answer
  • I <br>need help solving this
    10·2 answers
  • Consider a water pipe that branches into two smaller pipes. If the flow of water is 10 L/min in the main pipe and 4 L/min in one
    8·1 answer
  • Please help me on number 21
    13·1 answer
  • I will give brainiest to whoever answers correctly !!
    5·1 answer
  • -6x+3y=-7 x-intercept
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!