Answer:
20
Step-by-step explanation:
For the sake of the problem, let's make female workers "x" and male workers "y".
x+y<40 This equation shows that the total number of workers has a max of 40.
30x+20y<1,000 This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.
Now you can solve for x and y.
X+y<40
-y -y
X<-y+40
Substitute -y+40 in for X in the second equation
30(-y+40)+20y<1,000
-30y+1200+20y<1,000 Distribute
-10y+1,200<1,000 Combine like terms
-10y<-200 Subtract 1,200
y>20 Divide by -10; flip the sign
Since y>20, and y=male workers, you now know that the minimum
number of male workers he should send is 20
Answer:
x = - 2 or x = 5
Step-by-step explanation:
Given
3x² - 9x - 30 = 0 ← in standard form
Divide all terms by 3
x² - 3x - 10 = 0
To factor the quadratic
Consider the factors of the constant term (- 10) which sum to give the coefficient of the x- term (- 3)
The factors are - 5 and + 2, since
- 5 × 2 = - 10 and - 5 + 2 = - 3, thus
x² - 3x - 10 = 0
(x - 5)(x + 2) = 0
Equate each factor to zero and solve for x
x - 5 = 0 ⇒ x = 5
x + 2 = 0 ⇒ x = - 2
So basically, each number is equal to the two numbers below it added together.
See, 7 = 3+4, 8 = 5 +3, etc.
So, the top would be 16 + 17.
16 + 17 = 33
So 33 goes on top.
Answer: They are not perpendicular because their slopes are not negative reciprocals.
Step-by-step explanation:
For these two lines to be perpendicular, their slopes have to be negative reciprocals.
Slope of FG.
F = (-4, 1)
G = (0, -2)
= (Y₂ - Y₁) / (X₂ - X₁)
= (-2 - 1) / (0 + 4)
= -3/4
Slope of HJ
J = (0 , 4)
H = (-4, -2)
Slope = (Y₂ - Y₁) / (X₂ - X₁)
= (-2 - 4) / (-4 -0)
= 6/4
= 3/2
<em>The slopes of these lines are not negative reciprocals so these lines are not perpendicular. </em>
