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Arturiano [62]
4 years ago
6

Titan is special because

Physics
1 answer:
Nuetrik [128]3 years ago
8 0
It’s a good movie maybe. Since I like it as well
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If one doubles the emfs in a circuit and doubles the resistances in the circuit at the same time, what happens to the currents t
bija089 [108]

Answer:

Same

Explanation:

Let R be the resistance of the cell and E be the emf.

Let i be the current in the circuit.

i = E / R      ..... (1)

Now emf and resistance be doubled.

so, i' = 2E/2R = E/R

So, i' = i    (From equation (1)

Current remains same.

3 0
3 years ago
If the incoming photon had a frequency of 8.0 E14 Hz, would you have a photo-electron ejected?
cupoosta [38]

Yes.


In fact, from the graph we see that the threshold frequency (the minimum energy of the incoming energy needed to extract a photoelectron from the material) is 5.0 \cdot 10^{14} Hz (we see it because this is the frequency at which the maximum kinetic energy of the emitted electron is zero).


The incoming photon in this problem has a frequency of 8.0 E14 Hz, so above the threshold frequency, therefore it is enough to extract photoelectrons from the material.

4 0
4 years ago
A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 4.79 g coins stacked over the 28.8 cm mark, th
masha68 [24]

To solve the exercise, the key concept to be addressed is the Mass Center.

The center of mass of an object is measured as,

X_{cm} = \frac{\sum m_ix_i}{\sum m_i}

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

Our values are given by,

x_1 = 50cm

m_1 = ?

x_2 =28.8cm

m_2 = 4.79g

x_3 = 28.8cm

m_3 = 4.79g

X_{cm} = 38.4cm

Replacing the values in our previous equation we have,

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

38.4 = \frac{m_1(50)+2(28.8*4.79)}{m_1+2*4.79}

38.4(m_1+2*4.79)= m_1(50)+2(28.8*4.79)

38.4m_1 +367.872 = 50m_1+275.904

11.6m_1 = 91.968

m_1 = 7.928g

Therefore the mass of the meter stick is 7.928g

7 0
3 years ago
A capacitor is charged to a potential difference of 12v it delivers 40% of its stored energy to a lamp what is the final potenti
Korolek [52]
Call the capacitance C. 
<span>Note the energy in a capacitor with voltage V is E =½CV². </span>

<span>Initial energy = ½C(12)² = 72C </span>

<span>40% of energy is delivered, so 60% remains.in the capacitor. </span>
<span>Remaining energy = (60/100) x 72C =43.2C </span>

<span>If the final potential difference is X, the energy stored is ½CX² </span>
<span>½CX² = 43.2C </span>
<span>X² = 2 x 43.2 = 86.4 </span>
<span>X = 9.3V</span>
6 0
3 years ago
A canon is tilled back 30.0 degrees and shoots a cannon ball at 155 m/s. What is the
Umnica [9.8K]

Answer:

= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m

Therefore, highest point that the cannon ball reaches is 168.7m

Explanation:

the cannon is fired at an angle 30 o to the horizonatal with a speed of 155 m/s

highest point that the cannon ball reaches?

H_{max}=\frac{V^2\sin ^2 \theta}{2g}

g = 9.8m/s2

= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m

Therefore, highest point that the cannon ball reaches is 168.7m

6 0
4 years ago
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