Answer:
Explanation:
Ok, pick some idea from here
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Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
Total energy will remain the same
Answer:
<em>480m/s²</em>
Explanation:
Acceleration is the change in velocity of a body with respect to time;
Acceleration = change in velocity/change in time
change in velocity = 29,500 - 24,000
change in velocity= 5,500
Change in time = 55 - 5
change in time = 50secs
Substitute into the formula;
spaceships acceleration = 24000/50
spaceships acceleration = 480 m/s²
<em>Hence the spaceships acceleration is 480m/s²</em>
