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3 years ago

Emission spectrum for an element is

1 answer:

6 0

Answer: ...frequencies of electromagnetic radiation emitted due to an atom or molecule making a transition from a high energy state to a lower energy state

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Please help! Questions are in the picture

Mars2501 [29]

Answer:

3500j

0.250 kg

14.14 m/s

220500 j

93.91 m/s

Explanation:

K.E =1/2 m v^2

first question

1/2×700×10=3500 j

second question

2×78.2/25^2= 0.250 kg

Third question

8kj=8000j

root (2×8000/80)= 14.14 m/s

Last one

P.E=MGH

so it will be

P.E=50×450×9.8=220500 j

the speed

root (2×220500/50)=93.91 m/s

7 0

3 years ago

During a supernova, the outer layers of a star are blown off and the star's core shrinks down by a factor of 10,000 or more to f

Lana71 [14]

Answer:

a. the core will spin faster.

Explanation:

By law of conservation of angular momentum

(mvR)i= (mvR)f

m= mass of star

v= speed of star

R= radius of star

i= initial

f= final

since, size(R) of the star is reduced by factor of 10,000 and mass remains the same, the velocity must increase by the same factor to keep the angular momentum conserved.

Hence, a. the core will spin faster.

8 0

4 years ago

The fastest propeller-driven aircraft is the Russian TU-95/142, which canreach a maximum speed of 925 km/h. For this speed, calc

valentinak56 [21]

Answer:

The resultant displacement of plane = 1310.76 Km

Explanation:

Given that,

Speed of the plane = 925 Km/h

Therefore, in 1 hour plane travels 925 Km

From figure,

Displacement if it travels east for 1.5 h, AB = 1387.5 Km

Displacement if it travels north-west for 2 h, BC = 1850 Km

Angle formed between two displacement = 135°

The resultant displacement is given by the relation

AC² = AB² + BC² + 2 AB BC Cos θ

Substituting the values in the equations,

AC² = 1387.5² + 1850² + 2 x 1387.5 x 1850 x Cos 135°

= 1718095

AC = 1310.76

Therefore, the resultant displacement of plane is 1310.76 Km

7 0

3 years ago

A 1400.0 kg car crests a 3200.0 m pass in the mountains and briefly comes to rest. The car descends 1000 m before climbing and c

rjkz [21]

Answer:

a) v = 88.54 m/s

b) vf = 26.4 m/s

Explanation:

Given that;

m = 1400.0 kg

by using the energy conservation

loss in potential energy is equal to gain in kinetic energy

mg × ( 3200-2800) = 1/2 ×m×v²

1400 × 9.8 × 400 = 0.5 × 1400 × v²

5488000 = 700v²

v² = 5488000 / 700

v² = 7840

v = √7840

v = 88.54 m/s

Work done by all forces is equal to change in KE

W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)

we substitute

1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf² -0 )

488000 = 700 vf²

vf² = 488000 / 700

vf² = 697.1428

vf = √697.1428

vf = 26.4 m/s

4 0

3 years ago

Spheres of Charge: A metal sphere of radius 10 cm carries an excess charge of +2.0 μC. What is the magnitude of the electric fie

nadezda [96]

To solve this problem we will apply the concept related to the electric field. The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,

$E = \frac{kV}{r^2}$