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Andreas93 [3]
3 years ago
6

Consider an object on a rotating disk a distance r from its center, held in place on the disk by static friction. Which of the f

ollowing statements is not true concerning this object:
A) If the angular speed is constant, the object must have constant tangenial speed.
B) If the angular speed is constant, the object is not accelerated
C) The object has a tangenial acceleration only if the disk has an angular acceleration.
D) If the disk has an angular acceleration, the object hasboth a centripetal and a tangenial acceleration
E) The object always has a centripetal acceleration exceptwhen the angular speed is zero
Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

A) False

B) False

C) True

D) True

E) True

Explanation:

A) The formula for tangential speed v in term of angular speed ω and radius of rotation r is

v = \omega r

So if the angular speed is constant and 0, the tangential speed is also 0. A) is false

B) False because of the centripetal acceleration:

a_c = \omega^2 r

C) True because of the formula for tangential acceleration in term of angular acceleration α is

a_t = \alpha r

D) True because same as D), if it has angular acceleration, it would have a tangential acceleration. Also from B) the centripetal acceleration will come with time as soon as angular speed is generated by angular acceleration.

E) True and same explanation as from B)

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A large balloon of mass 210 kg is filled with helium gas until its volume is 329 m3. Assume the density of air is 1.29 kg/m3 and
Nastasia [14]

(a) See figure in attachment (please note that the image should be rotated by 90 degrees clockwise)

There are only two forces acting on the balloon, if we neglect air resistance:

- The weight of the balloon, labelled with W, whose magnitude is

W=mg

where m is the mass of the balloon+the helium gas inside and g is the acceleration due to gravity, and whose direction is downward

- The Buoyant force, labelled with B, whose magnitude is

B=\rho_a V g

where \rho_a is the air density, V is the volume of the balloon and g the acceleration due to gravity, and where the direction is upward

(b) 4159 N

The buoyant force is given by

B=\rho_a V g

where \rho_a is the air density, V is the volume of the balloon and g the acceleration due to gravity.

In this case we have

\rho_a = 1.29 kg/m^3 is the air density

V=329 m^3 is the volume of the balloon

g = 9.8 m/s^2 is the acceleration due to gravity

So the buoyant force is

B=(1.29 kg/m^3)(329 m^3)(9.8 m/s^2)=4159 N

(c) 1524 N

The mass of the helium gas inside the balloon is

m_h=\rho_h V=(0.179 kg/m^3)(329 m^3)=59 kg

where \rho_h is the helium density; so we the total mass of the balloon+helium gas inside is

m=m_h+m_b=59 kg+210 kg=269 kg

So now we can find the weight of the balloon:

W=mg=(269 kg)(9.8 m/s^2)=2635 N

And so, the net force on the balloon is

F=B-W=4159 N-2635 N=1524 N

(d) The balloon will rise

Explanation: we said that there are only two forces acting on the balloon: the buoyant force, upward, and the weight, downward. Since the magnitude of the buoyant force is larger than the magnitude of the weigth, this means that the net force on the balloon points upward, so according to Newton's second law, the balloon will have an acceleration pointing upward, so it will rise.

(e) 155 kg

The maximum additional mass that the balloon can support in equilibrium can be found by requiring that the buoyant force is equal to the new weight of the balloon:

W'=(m'+m)g=B

where m' is the additional mass. Re-arranging the equation for m', we find

m'=\frac{B}{g}-m=\frac{4159 N}{9.8 m/s^2}-269 kg=155 kg

(f) The balloon and its load will accelerate upward.

If the mass of the load is less than the value calculated in the previous part (155 kg), the balloon will accelerate upward, because the buoyant force will still be larger than the weight of the balloon, so the net force will still be pointing upward.

(g) The decrease in air density as the altitude increases

As the balloon rises and goes higher, the density of the air in the atmosphere decreases. As a result, the buoyant force that pushes the balloon upward will decrease, according to the formula

B=\rho_a V g

So, at a certain altitude h, the buoyant force will be no longer greater than the weight of the balloon, therefore the net force will become zero and the balloon will no longer rise.

4 0
3 years ago
A block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp
GuDViN [60]

The work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.

<h3>What is work done?</h3>

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is  a block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.

From the Newton's law of motion,

ma =F-mg sinθ =0

So, the force F = mg sinθ

Plug the values, we get

F = 620N x sin 23.5°

F = 247.224 N

Work done by motor is  W= F x d

The force is equal to the weight F = mg

So, W = 247.224 x 14.1

W = 3.486 kJ

Thus, the work done by the force in pulling the block all the way to the top of the ramp is  3.486 kJ.

Learn more about Work done

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7 0
2 years ago
What is the most abundant gas in the atmosphere?
Snowcat [4.5K]

Answer: Nitrogen

Explanation: Nitrogen makes up 78% of the atmosphere, Oxygen makes up 21%, and Argon 0.9%.

Water vaper makes up between 1-4%, depending on the region.

Carbon Dioxide makes up only about 0.04%.

8 0
3 years ago
if for every force there is an equal and opposite reaction force, how is it possible for an object to accelerate
lesya692 [45]

Answer:

By the use of the reaction force one body is able to accelerate because it is not fixed to a rigid support which offers a materialistic resistance.

Explanation:

For every  force there is an equal and opposite reaction is stated in the Newton's third law of motion holds true universally.

This law accounts for the acceleration of the bodies with respect to the object that applies force on the other body. The acceleration is possible when iether one of the body is fixed and cannot move or when that both the bodies are not fixed can move.

  • For example consider a rocket with its engine started. This rocket generates upthrust by conversion of chemical energy of the fuel into the mechanical energy applying force on the launchpad. When this force is large enough it to lift the rocket then the rocket starts moving in the air and it  accelerates. Now, when it is in the air or in vacuum during the course of its journey it uses the reaction of the burnt gases of the fuel to change the momentum.

This is in accordance with the Newton's second law of motion, stating that the Force is directly proportional to the rate of change in momentum.

8 0
3 years ago
An electron in the first energy level of the electron cloud has an electron in the third energy level
lukranit [14]

Answer:

a lower energy than

Explanation:

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4 years ago
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