Step-by-step explanation:
(x²-1)(x+1)≥0
As it has two multiples,
Therefore,
Either,
x²-1≥0
x²≥0+1
x²≥1
x≤√1
x≤1
Or,
x+1≥0
x≥-1
Answer:
hope it helps you see the attachment for further information
D. (I used 3.14 as pi so my answer was a little off so I just went with the one closest to my answer)
Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
Answer:
question 9
= –12
while question 11=, x= –72
Step-by-step explanation:
question 9=
u= –16+4= –12
question 11=
cross multiplication
x = -36 multiplied by 2 =
-72
I HOPE THIS HELPED IF WRONG IM SORRY
