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blagie [28]
4 years ago
5

Given the following chemical reaction:202 CH4 CO2 2 H20What mass of CH4 is required to completely react with 100 grams of O2?

Chemistry
1 answer:
Helga [31]4 years ago
7 0
Molar mass:

O₂ = 32.0 g /mol             CH₄ = 16.0 g/mol

2 O₂ + CH₄ = CO₂ + 2 H₂O

2 x 32 g O₂ ---------------> 16 g CH₄
100 g O₂ ------------------> ( mass of CH₄)

mass of CH₄ = 100 x 16 / 2 x 32

mass of CH₄ = 1600 / 64

= 25 g of CH₄

hope this helps!
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What are the products of Nal+CaCl2? <br><br> Please help!
miss Akunina [59]

Answer:

There are no products.  

Explanation:

A possible reaction could be the double displacement reaction

2NaI(aq) + CaCl₂ ⟶ 2NaCl(aq) + CaI₂(aq)

However, there is no reaction because the halide salts of Group 1 and Group 2 metals are soluble.

3 0
4 years ago
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
4 years ago
What type of reaction takes place when using this enzyme (endergonic or exergonic)?
zalisa [80]

Answer:

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3 0
3 years ago
A 37.2-g sample of lead (Pb) pellets at 20°C is mixed with a 62.7-g sample of lead pellets at the same temperature. What are th
Vesnalui [34]

Answer:

Mass of sample is 99.9 g, density of ample is 11.35 g/cm^{3} and temperature of sample is 20^{0}\textrm{C}

Explanation:

Mass is an additive property. Therefore mass of combined sample is summation of masses of two pellets.

Mass of combined sample = (37.2+62.7) g = 99.9 g

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Density of combined sample = 11.35 g/cm^{3}

Temperature is an intensive property. Therefore temperature of combined sample of lead will be same as with individual pellets.

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3 years ago
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mafiozo [28]

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4 years ago
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