Calculate the decrease in temperature when 6.00 L at 25.0 °C is compressed to 2.50 L.

Chemistry

1 answer:

N76 [4]2 years ago

4 0

Answer:

-149.0K

Explanation:

Charles's law states that the volume of a gas is directly proportional to the absolute temperature under constant pressure.

The equation is:

V1/T1 = V2/T2

<em>Where V1 is initial volume = 6.00L</em>

<em>T1 is absolute initial temperature = 25.0°C + 273 = 298K</em>

<em>V2 is final volume = 2.50L</em>

<em>T2 is our incognite</em>

<em />

Replacing:

6.00L/298K = 2.50L/T2

T2 = 2.50L * 298K / 6.00L

T2 = 124.17K

The temperature is 124.17K - 273.15K =

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