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hammer [34]
3 years ago
14

Calculate the decrease in temperature when 6.00 L at 25.0 °C is compressed to 2.50 L.

Chemistry
1 answer:
N76 [4]3 years ago
4 0

Answer:

-149.0K

Explanation:

Charles's law states that the volume of a gas is directly proportional to the absolute temperature under constant pressure.

The equation is:

V1/T1 = V2/T2

<em>Where V1 is initial volume = 6.00L</em>

<em>T1 is absolute initial temperature = 25.0°C + 273 = 298K</em>

<em>V2 is final volume = 2.50L</em>

<em>T2 is our incognite</em>

<em />

Replacing:

6.00L/298K = 2.50L/T2

T2 = 2.50L * 298K / 6.00L

T2 = 124.17K

The temperature is 124.17K - 273.15K =

<h3>-149.0K</h3>

<em />

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determine the average volume from the following volume reading: 3.00ml, 2.0ml, 2.987 x 10^-3 l, and 3.4856 ml
lesya [120]

Answer:

The average of given values is 2.1221 ml

Explanation:

Given data:

Given measurements = 3.00 ml , 2.0 ml, 2.987 × 10⁻³ml , 3.4856 ml

Average value of given measurements = ?

Solution:

Formula:

Average value = sum of all measurement  / total number of measurements

2.987 × 10⁻³ml = 0.002987 ml

Now we will put the  values.

Average value = 3.00 ml + 2.0 ml + 0.002987 ml+ 3.4856 ml / 4

Average value = 8.488587 ml / 4

Average value =  2.1221 ml

The average of given values is 2.1221 ml

8 0
3 years ago
B. The following reaction takes place in a basic solution. (7 points)
Natali5045456 [20]

<u>Answer:</u> The final equation has hydroxide ions which indicate that the reaction has occurred in a basic medium.

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

The given redox reaction follows:

MnO_4^-(aq)+NO_2^-(aq)\rightarrow MnO_2(s)+NO_3^-(aq)

To balance the given redox reaction in basic medium, there are few steps to be followed:

  • Writing the given oxidation and reduction half-reactions for the given equation with the correct number of electrons

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-

  • Multiply each half-reaction by the correct number in order to balance charges for the two half-reactions

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-         ( × 3)

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-             ( × 2)

The half-reactions now become:

Oxidation half-reaction: 3NO_2^-+6OH^-\rightarrow 3NO_3^-+3H_2O+6e^-

Reduction half-reaction: 2MnO_4^-+4H_2O+3e^-\rightarrow 2MnO_2+8OH^-

  • Add the equations and simplify to get a balanced equation

Overall redox reaction: 3NO_2^-+2MnO_4^-+H_2O\rightarrow 3NO_3^-+2MnO_2+2OH^-

As we can see that in the overall redox reaction, hydroxide ions are released in the solution. Thus, making it a basic solution

3 0
3 years ago
650.J is the same amount of energy as? <br>2720cal<br>1550cal<br>650.cal<br>2.72cal
Oksi-84 [34.3K]

<u>Ans: 650 J = 155 calories</u>


<u>Given:</u>

Energy in joules = 650 J

<u>To determine:</u>

The energy in calories

<u>Explanation:</u>

1 joule = 0.2388 calories

Therefore, 650 joules = 0.2388 calories * 650 J/1 J = 155 calories

4 0
4 years ago
Read 2 more answers
Find the percent composition of C7H5N3O6
Oksana_A [137]

Finding percent composition is fairly easy. You only need to divide the mass of an element by the total mass of the compound. We can do this one element at a time.

First, let's find the total mass by using the masses of the elements given on the periodic table.

7 x 12.011 (mass of Carbon) = 84.077

5 x 1.008 (mass of Hydrogen) = 5.04

3 x 14.007 (mass of Nitrogen) = 42.021

6 x 15.999 (mass of Oxygen) = 95.994

Add all of those pieces together.

84.077 + 5.04 + 42.021 + 95.994 = 227.132 g/mol is your total. Since we also just found the mass of each individual element, the next step will be very easy.

Carbon: 84.077 / 227.132 = 0.37016 ≈ 37.01 %

Hydrogen: 5.04 / 227.132 = 0.022189 ≈ 2.22 %

Nitrogen: 42.021 / 227.132 = 0.185 ≈ 18.5 %

Oxygen: 95.994 / 227.132 = 0.42263 ≈ 42.26 %

You can check your work by making sure they add up to 100%. The ones I just found add up to 99.99, which is close enough. A small difference (no more than 0.03 in my experience) is just a matter of where you rounded your numbers.

5 0
3 years ago
What happened to the salt molecules when they were added to cold water
Nimfa-mama [501]
Cooler water molecules are denser than warm water and will not allow much of the salt to dissolve
8 0
3 years ago
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