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hammer [34]
2 years ago
14

Calculate the decrease in temperature when 6.00 L at 25.0 °C is compressed to 2.50 L.

Chemistry
1 answer:
N76 [4]2 years ago
4 0

Answer:

-149.0K

Explanation:

Charles's law states that the volume of a gas is directly proportional to the absolute temperature under constant pressure.

The equation is:

V1/T1 = V2/T2

<em>Where V1 is initial volume = 6.00L</em>

<em>T1 is absolute initial temperature = 25.0°C + 273 = 298K</em>

<em>V2 is final volume = 2.50L</em>

<em>T2 is our incognite</em>

<em />

Replacing:

6.00L/298K = 2.50L/T2

T2 = 2.50L * 298K / 6.00L

T2 = 124.17K

The temperature is 124.17K - 273.15K =

<h3>-149.0K</h3>

<em />

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2 years ago
Olympic cyclists fill their tires with helium to make them lighter. Assume that the volume of the tire is 860 mL , that it is fi
nata0808 [166]

Answer:

a)  the mass of air = 8.24 grams

b) the mass of helium = 1.14 grams

c) the mass difference = 7.10 grams

Explanation:

Step 1: Data given

Volume of the tire = 860 mL

Total pressure = 120 psi

Temperature = 26°C

molar mass of air = 28.8 g/mol

Step 2:  Convert psi to atm

(

120 psi) (1 atm / 14.7 psi) = 8.163

Step 4: Calculate moles

PV = nRT

 ⇒ with P = the pressure = 8.163 atm

⇒ with V = the volume = 860 mL = 0.860 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the universal gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 26 °C = 299 Kelvin

n = (8163*0.860)/(0.08206*299)

n = 0.2861 moles of gas

Step 5: Calculate the mass of air in an air-filled tire.

Mass = moles * molar mass

Mass = (0.2861 moles of gas) (28.8 g/mol)  

Mass = 8.24 grams

Step 6: Calculate the mass of helium in a helium- filled tire.

mass of helium = 0.2861 moles of gas * 4 g/mol)  

mass of helium  = 1.14 grams

Step 7: What is the mass difference between the two?

Δmass=  8.24 grams -  1.14 grams

Δmass= 7.10 grams

8 0
3 years ago
Ca(s) + O₂(g) + S(s) → CaSO4(s)
san4es73 [151]

The mass of Calcium required to complete this reaction is 4.008 g.

  • Law of conservation of mass states that In a closed system, mass cannot be produced or destroyed, but it can be changed from one form to another.
  • The mass of the chemical constituents before a chemical reaction is equal to the mass of the constituents after the reaction.
  • In several disciplines, including chemistry, mechanics, and fluid dynamics, the idea of mass conservation is widely applied.

In the given reaction mass of product after completion of reaction is 13.614 g that means total mass of constituents before reaction should also be 13.614.

So,

mass of Ca + mass of O₂ + mass of S = mass of CaSO4

Ca + 6.400 g + 3.206 g = 13.614 g

mass of Ca = 13.614 - 9.606 = 4.008 g

Therefore, by law of conservation of mass 4.008 g of Ca is required for the completion of the reaction.

Learn more about mass conservation here:

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5 0
1 year ago
3. Explain the relationship between power, energy and time.
likoan [24]
There is a very simple relationship between the three. First off, power is the amount of energy used over a certain amount of time. Energy is the capacity of carrying out that power. Lastly, time depends on how much energy you have to exert the work.

Hope this helps :)
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