Look at the rectangle and the square:
2 answers:
Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ = ≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM = ≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ
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Answer:
Step-by-step explanation:
The problem is:
<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>
<em />
This problem is about algebraic language. We just need to express the ordinaty language into an equation.
We know the words less means difference. So, let's call Argos' weight and
Roco's weight. We can expresse the given problem as
Notice that we applied a difference due to the word "less" in the problem.
Therefore, Argo's weight is given by the expression