Look at the rectangle and the square:
2 answers:
Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ = ≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM = ≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ
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-5x-12>6x-4
To Solve the inequality we need to get x alone
-5x-12>6x-4
first we remove -12, for that we add 12 on both sides
-5x-12+12>6x-4+12
-5x > 6x +8
Now subtract 6x from both sides
-5x -6x> 6x-6x +8
-11x > 8
Divide by -11. when we divide by -11 we flip the inequality . so > becomes <
We need to give the answer in interval notation.
x is less than -8/11 so x value starts from -8/1 and goes to -infinity(left)
So interval notation is (-∞, )