Find f(3) given f(x) = -3x^3 + 2x^2 + 24<br> A. 123<br> B. -39<br> C. 69<br> D. 99

Triangle ABC maps to triangle A′B′C′ by a 90∘ rotation counterclockwise about the origin.

Tresset [83]

The answer is 90 units hope this helps

7 0

3 years ago

May I have some help with this?

madam [21]

Answer:

a. tanB= 3/2

Step-by-step explanation:

tanA= p/b =:2/3

For angle A,

p= 2

b=3

For angle B,

p = 3

b=2

So, TanB = 3/2

6 0

3 years ago

For △RST and △UVW, ∠R≅∠U, ST≅VW, and ∠S≅∠v. Explain how you can prove △RST ≅△UVW by ASA

monitta

Answer:

See explanation below.

Step-by-step explanation:

Note that in △RST and △UVW

m∠T=180°-m∠R-m∠S;
m∠W=180°-m∠U-m∠V.

Since ∠R≅∠U and ∠S≅∠V, then ∠T≅∠W.

In ΔRST and ΔUVW:

∠S≅∠V (given);
∠T≅∠W (proved);
ST≅VW (given).

ASA theorem that states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

By ASA theorem ΔRST≅ΔUVW.

6 0

3 years ago

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan

torisob [31]

The point slope form of the line which passes through the points $(-5,-1)$ and $(10,-7)$ is $\fbox{\begin\\\ \math 2x+5y=-15\\\end{minispace}}$ i.e., $\fbox{\begin\\\ \bf option C\\\end{minispace}}$ .

Further explanation:

It is given that line passes through the points $(-5,-1)$ and $(10,-7)$ .

The objective is to determine the point slope form of the line which passes through the points $(-5,-1)$ and $(10,-7)$ .

The options given are as follows:

Option A: 2x-5y=-15

Option B: 2x-5y=-17

Option C: 2x+5y=-15

Option D: 2x+5y=-17

Consider the point $(-5,-1)$ as $(x_{1},y_{1})$ and $(10,-7)$ as $(x_{2},y_{2})$ .

Slope of a curve is defined as the change in the value of $y$ with respect to change in value of $x$ .

The slope of the line is calculated as follows:

$\fbox{\begin\\\ \math m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\end{minispace}}$

To obtain the value of slope substitute the value of $x_{1},y_{1},x_{2},y_{2}$ in the above equation.

$\begin{aligned}m&=\dfrac{-7-(-1)}{10-(-5)}\\&=\dfrac{-6}{15}\\&=\dfrac{-2}{5}\end{aligned}$

Therefore, the slope of the line is $\fbox{\begin\\\ \math m=\dfrac{-2}{5}\\\end{minispace}}$

The general way to express the equation of a line in its point slope form is as follows:

$\fbox{\begin\\\ \math (y-y_{1})=m(x-x_{1})\\\end{minispace}}$

To obtain the point slope form of the equation of the line substitute the value of $m$ , $x_{1}$ and $y_{1}$ in the above equation.

$\begin{aligned}(y-(-1))&=\dfrac{-2}{5}(x-(-5))\\(y+1)&=\dfrac{-2}{5}(x+5)\\5y+5&=-2x-10\\5y+2x&=-15\end{aligned}$

From the above calculation it is concluded that the point slope form the equation of a line is $\fbox{\begin\\\ \math 5y+2x=-15\\\end{minispace}}$

Figure 1 (attached in the end) represents the graph of the function $5y+2x=-15$ .

This implies that the correct option for the point slope form of the line is option C.

Therefore, the point slope form of the line which passes through the points $(-5,-1)$ and $(10,-7)$ is $2x+5y=-15$ i.e., option C.

Learn more:

1. A problem to complete the square of quadratic function brainly.com/question/12992613

2. A problem to determine the slope intercept form of a line brainly.com/question/1473992

3. Inverse function brainly.com/question/1632445.

Answer details

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: Equation, linear equation, slope, intercept, x-intercept, y-intercept, intersect, graph, curve, slope intercept form, line, y=3x/2-3, standard form, point slope form.

6 0

3 years ago

Read 2 more answers

What angle do the minute and hour hands of a clock make at 8:00

svlad2 [7]

The angle that the minute and hour hands make when they are at 8:00 is obtuse

6 0

4 years ago

Find f(3) given f(x) = -3x^3 + 2x^2 + 24 A. 123 B. -39 C. 69 D. 99