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musickatia [10]
4 years ago
12

Looking at this landscape, what compositional elements do you see?

Computers and Technology
1 answer:
Musya8 [376]4 years ago
7 0
I’m sorry but I can’t see anything. I won’t be able to answer this question if there is no picture.
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The price elasticity of demand for mobile phones a. will be higher if there is an improvement in the production technology. b. w
rodikova [14]

Answer:

b. will be lower if consumers perceive mobile phones to be a necessity.

Explanation:

The price elasticity of demand is described as the percentage variation in the demanded quantity of service or goods divided by the change in the percentage of the price. And henceforth it describes the responsiveness of the demanded quantity to a price change. And now if the mobile phones are thought of as being the necessity then the price will increase as demand will increase, and hence the price elasticity of demand will be lower. And if there is an improvement in the production technology then the price will be lowered, and hence price elasticity of demand will be less as the change in the percentage of the price will be negative. And the exact definition of it as we have described above. Hence, b is correct options.

3 0
3 years ago
If a _____ error appears when you run a macro that has worked in the past, some part of the macro code no longer makes sense to
Burka [1]
If a run-time error appears when you run a macro that has worked in the past, some part of the macro code no longer makes sense to excel, ehere run-time denotes <span> the time during which a program is running</span>
This error occurs while the program is running.
Running<span> out of memorywill results in  a </span>run-time error.
5 0
3 years ago
A teacher has five students who have taken four tests. The teacher uses the following grading scale to assign a letter grade to
AlladinOne [14]

Answer:

#include <iostream>

using namespace std;

int main()

{

const int numofStudents = 5;//number of students

const int numofTests = 2;//number of tests taken by students

const int grade = 5;//number of grades available

char letter[grade] = { 'A','B','C','D','F' };

double table[numofStudents][numofTests];//defining 2darray with names and scores

string names[numofStudents];//storing names of students

for (int num = 0; num < numofStudents; num++)//storing names and scores of students

{

 cout << "Enter student's name: ";

 cin >> names[num];

 for (int test = 0; test < numofTests; test++)//scores loop

 {

  cout << "Enter the test score: ";

  cin >> table[num][test];

  if (table[num][test] < 0 || table[num][test]>100)//input validation

  {

   cout << "Invalid input. Try again" << endl;

   cin >> table[num][test];//input again

  }

 }

}

for (int i = 0;i < numofStudents;i++)//calculating averages and grades

{

 int sum = 0;

 cout << "Test scores for " << names[i] << ": " << endl;

 for (int j = 0;j < numofTests;j++)

 {

  cout << table[i][j] << " ";

  sum += table[i][j];//summing scores

 }

 cout << endl;

 float average = (float)sum / numofTests;//calculating the average

 cout << "Making an average of: "<< average;

 if (average <= 100 && average >= 90)//assigning a grade

 {

  cout << " and has received an " << letter[0];

 }

 else if (average <= 89 && average >= 80)

 {

  cout << " and has received a " << letter[1];

 }

 else if (average <= 79 && average >= 70)

 {

  cout << " and has received a " << letter[2];

 }

 else if (average <= 69 && average >= 60)

 {

  cout << " and has received a " << letter[3];

 }

 else if (average <= 59 && average >= 0)

 {

  cout << " and has received an " << letter[4];

 }

 else

 {

  cout << "Invalid scores entered." << endl;

 }

 cout << endl;

}

 return 0;

}

Explanation:

We first define the number of students, number of tests and number of grades available for assignments. We then fill in the 2D array of students names and their scores making sure assigning more than 100 and less than 0 is not allowed. We then sum the scores and retrieve an average. Using the average, a letter grade is assigned to that individual.

6 0
3 years ago
Input an int between 0 and 100 and print the numbers between it and 100, including the number itself and the number 100. If the
Murrr4er [49]

import java.util.Scanner;

public class JavaApplication42 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       int count = 0;

       System.out.println("Enter an integer between 0 and 100");

       int num = scan.nextInt();

       if (num <= 0 || num >= 100){

           System.out.println("error");

       }

       else{

           while(num <= 100){

               if (count == 20){

                   System.out.println("");

                   count = 0;

               }

               else{

                   System.out.print(num+" ");

                   count++;

                   num++;

               }

           }

       }

   }

   

}

I hope this helps!

6 0
3 years ago
Online
Tanya [424]

Answer:

i can't understand what u want to say

5 0
3 years ago
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