3 years ago

Please help me on this question (4a)

1 answer:

5 0

You have to draw the arrow going out of the coffee cup and into the environment. Since the coffee is hot, heat will ecscape in order for it to reach room temperature

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Sn, Si, C

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2 years ago

If i add 25 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be ?

marshall27 [118]

1000 mL=1L

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125 mL = 0.125 L

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6 0

3 years ago

The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int

bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

$A=\epsilon \times c\times l$

$A=\log \frac{I_o}{I}$

$\log \frac{I_o}{I}=\epsilon \times c\times l$

where,

A = absorbance of solution

c = concentration of solution

$\epsilon$ = Molar absorption coefficient

l = path length

$I_o$ = incident light

$I$ = transmitted light

Given :

l = 1 cm, c = 1 mg/mL , $\epsilon = 15,000 M^{-1}cm^{-1}$

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

c = 1 mg /mL = ${1mg /mL}{\text{Molar mass of myoglobin}}$

$c = \frac{1 mg/mL}{ 17800 g/mol} = 5.6179\times 10^{-5} mol/L$

1 mg = 0.001 g, 1 mL = 0.001 L

$A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm$

$A=0.8426 \approx 0.84$

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

5 0

3 years ago