Answer:
-266 kJ
Explanation:
There is some info missing. I think this is the original question.
<em>A mixture of nitrogen and neon gas is expanded from a volume of 53.0 L to a volume of 90.0 L, while the pressure is held constant at 71.0 atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.</em>
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Given data
Initial volume = 53.0 L
Final volume = 90.0 L
Pressure = 71.0 atm
We can find the work (w) associated with the expansion of the gaseous mixture using the following expression.
w = - P × ΔV = - 71.0 atm × (90.0 L - 53.0 L) = -2.63 × 10³ atm . L
w = -2.63 × 10³ atm . L × (101.3 J/ 1 atm . L) = -2.66 × 10⁵ J = -266 kJ
The negative sign means that the system does work on the surroundings.
Hi there! Let's solve this problem shall we!
⠀Volume = 10g
Mass = 2 mL
In this specific problem, they are asking us to find the <u><em>density </em></u>of the object. So,<u><em> using the information given to us</em></u> (volume and mass), let's solve the problem!
Now, if you remember, D = M ÷ V
So, let's fill in the blanks!
D = Our unknown value
M = 2mL
V = 10g
Here is the filled out formula:
D = M ÷ V
D = 2mL ÷ 10g
D = 5 g/mL
*Make sure you put the units for your final solution!*
Since there is more energy added as heat rises, the particles disperse and have larger movements.
Answer:
1. MgCl2 + Zn -> Mg + ZnCl2
2. 2Al + 6H2O(g) -> 2Al(OH)3 + 3H2
3. 2Cd + O2 -> 2CdO
4. I2 + KF -> it's not going to react
5. Zn + H2SO4 -> ZnSO4 + H2
6.2KBr + Cl2 -> 2KCl + Br2
7. AgNO3 + Na -> NaNO3 + Ag
8. 2NaCl + F2 -> 2NaF + Cl2
9. AgNO3 + Mg(NO3)2 + Ag
10. Ni + H2SO4 -> NiSO4 + H2
11. Al + K2SO4
12. FeCl3 + 3Mn-> 3MnCl + Fe
13. 2Na + 2H2O -> 2NaOH + H2
14. 2K + MgBr2 -> 2KBr + Mg
15. Zn + Pb(NO3)2 -> Pb + Zn(NO3)2
16. 2AlBr3+ 3Cl2 -> 2AlCl3 + 3Br2
