Answer:
3.0 L O₂
Explanation:
If CO reacts at STP, it means that there are 1.0 moles of CO. To find the moles of O₂, you need to use the mole-to-mole ratio from the given equation.
1.0 moles CO 1 mole O₂
---------------------- x --------------------- = 0.5 moles O₂
2 moles CO
To calculate the liters of oxygen, you need to use Avogadro's Law:
V₁ / N₁ = V₂ / N₂
In this equation, "V₁" and "N₁" represent the volume and moles of the first molecule. "V₂" and "N₂" represent the volume and moles of the second molecule. You can plug the given and calculated values into the equation and simplify to isolate V₂.
V₁ = 6.0 L V₂ = ? L
N₁ = 1.0 moles N₂ = 0.5 moles
V₁ / N₁ = V₂ / N₂ <----- Avogadro's Law
(6.0 L) / (1.0 moles) = V₂ / (0.5 moles) <----- Insert values
6.0 = V₂ / (0.5 moles) <----- Simplify left side
3.0 = V₂ <----- Multiply both sides by 0.5
**I am not 100% confident on this answer. Please let me know if it is incorrect**
Answer: The final concentration of aluminum cation is 0.335 M.
Explanation:
Given: 
= 47.8 mL (1 mL = 0.001 L) = 0.0478 L
= 0.321 M, 
= 21.8 mL = 0.0218 L, 
= 0.366 M
As concentration of a substance is the moles of solute divided by volume of solution.
Hence, concentration of aluminum cation is calculated as follows.
![[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}](https://tex.z-dn.net/?f=%5BAl%5E%7B3%2B%7D%5D%20%3D%20%5Cfrac%7BM_%7B1%7DV_%7B1%7D%20%2B%20M_%7B2%7DV_%7B2%7D%7D%7BV_%7B1%7D%20%2B%20V_%7B2%7D%7D)
Substitute the values into above formula as follows.
![[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}\\= \frac{0.321 M \times 0.0478 L + 0.366 M \times 0.0218 L}{0.0478 L + 0.0218 L}\\= \frac{0.0153438 + 0.0079788}{0.0696}\\= 0.335 M](https://tex.z-dn.net/?f=%5BAl%5E%7B3%2B%7D%5D%20%3D%20%5Cfrac%7BM_%7B1%7DV_%7B1%7D%20%2B%20M_%7B2%7DV_%7B2%7D%7D%7BV_%7B1%7D%20%2B%20V_%7B2%7D%7D%5C%5C%3D%20%5Cfrac%7B0.321%20M%20%5Ctimes%200.0478%20L%20%2B%200.366%20M%20%5Ctimes%200.0218%20L%7D%7B0.0478%20L%20%2B%200.0218%20L%7D%5C%5C%3D%20%5Cfrac%7B0.0153438%20%2B%200.0079788%7D%7B0.0696%7D%5C%5C%3D%200.335%20M)
Thus, we can conclude that the final concentration of aluminum cation is 0.335 M.
During a tornado warning stay safe: gather as much food and water and other essentials and bunker down in the most safest place in the house like the bathroom or closet.
Compare and contrast:
A watch helps give a time stamp if or when a tornado will come and a waning means the tornado is here. Both say when a tornado is coming.
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>
➷ The correct answer would be A. Agitation (i.e. stirring)
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✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
To find<span> the </span>valence electrons in an atom<span>, identify what group the element is in. An element in group 1A has 1 </span>valence electron<span>. For example, Li is in group 1A, so that means it has one </span>valence electron. If the element is in group 2A, then it has two valence electrons<span>.</span>
