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olga nikolaevna [1]
3 years ago
12

What is the equation of the following line? Be sure to scroll down first to see all answer options.

Mathematics
2 answers:
Masja [62]3 years ago
7 0

The equation of the following line is D. y = -6x

<h3>Further explanation</h3>

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )} }

Let us tackle the problem.

From the attached picture, we can see a straight line through two points , (0,0) and (-½ , 3).

Let :

( 0 , 0 ) → ( x₁ , y₁ )

( -½ , 3 ) → ( x₂ , y₂ )

We can find the equation of solid line passing through points (x₁,y₁) and (x₂,y₂) by using this formula :

\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}

\frac{y - 0}{3 - 0} = \frac{x - 0}{-\frac{1}{2} - 0}

\frac{y}{3} = \frac{x}{-\frac{1}{2}}

\frac{y}{3} = -2x

y = 3 \times (-2x)

\large {\boxed {y = -6x}}

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Equation , Line , Variable , Line , Gradient , Point

Harrizon [31]3 years ago
6 0
<h3><u>Answer:</u></h3>

Hence, the equation of line is:

y= -6x

<h3><u>Step-by-step explanation:</u></h3>

Clearly from the graph we could see that the line passes through the point (0,0) and (-1/2,3).

Also we know that the equation of a line passing through (a,b) and (c,d) is given as:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Here we have:

(a,b)=(0,0) and (c,d)=(-1/2,3)

Hence, the equation of line is:

y-0=\dfrac{3-0}{-\dfrac{1}{2}-0}\times (x-0)\\\\\\\\y=\dfrac{3}{\dfrac{-1}{2}}\times x\\\\y=3\times (-2)\times x\\\\y=-6x

Hence, the equation of line is:

y= -6x

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