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eduard
3 years ago
9

Simplify and state restrictions.

Mathematics
1 answer:
Allisa [31]3 years ago
6 0

Answer:

We have the equation

\frac{4*a^2*b^2*c}{-3*a*b} + \frac{8c^2}{15}

First, we want the same denominator in both equations, so we can multiply in the left by 5, and in the right bt -ab, and now we have:

\frac{20*a^2*b^2*c}{-15*a*b} + \frac{-ab8c^2}{-15ab} = \frac{-20*a^2*b^2*c +8*a*b*c^2}{15*a*b}

Now we have all in the same rational.

The only restriction in this type of equation is that the denominator never can be zero.

so 15*a*b = 0 is a restriction:

This means that a can not be zero, and b can not be zero.

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Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.
Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given E(-2,3), F(1,6)

|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given F(1,6), G(4,3)

|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given G(4,3), H(1,0)

|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}

Given E (−2, 3), H (1, 0)

|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}

<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|=\frac{6-3}{1+2} =\frac{3}{3}=1

Segment GH, G (4, 3), H (1, 0)

Slope of |GH|= \frac{0-3}{1-4} =\frac{-3}{-3}=1

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0
3 years ago
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Volume =πr²*h=π*7²*4=196π
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3 years ago
1.
Elan Coil [88]

Answer:

Step-by-step explanation:

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4 0
3 years ago
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I.
Kaylis [27]
It’s A because (-2)2+(4)2-2(-2)+4(4)+8=0
-4+8+4+-16+8
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16 -16 =0
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3 years ago
The probability distribution for a random variable x is given in the table. -5 -3 -2 0 2 3 Probability .17 .13 33 16 11 10 Find
IgorLugansk [536]

Answer:

0.79

Step-by-step explanation:

add up the probability that is less than or equal to  0, which is 0.17+0.13+0.33+0.16 = 0.79

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