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3 years ago

6

Can someone please help me with this

1 answer:

dedylja [7]3 years ago

5 0

I think it would be most likely A the first one.

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What is the difference between explicit and recursive sequences ?

Anna71 [15]

An explicit formula for a sequence allows you to find the value of any term in the sequence. A recursive formula for a sequence allows you to find the value of the nth term in the sequence if you know the value of the (n-1)th term in the sequence.

7 0

3 years ago

Read 2 more answers

Which decimal number is equal to 318 ? 0.167 0.16¯ 0.16¯¯¯¯ 0.167¯¯¯¯¯

skad [1K]

Answer:

3/18 = 1/6 =.16666666.....

.16(would be repeating)

your choice D and A are the same, and choice C and B are the same!

hope this helps!

7 0

3 years ago

6. Let f and g be differentiable functions

Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate $h(x)=f(x)g(x)$ we will need the product rule:

$h'(x)=f'(x)g(x)+f(x)g'(x)$ .

We have $h'(x)=f(x)g'(x)$ , so the following equation is true by the transitive property:

$f'(x)g(x)+f(x)g'(x)=f(x)g'(x)$

By subtraction property we have:

$f'(x)g(x)=0$

Since $g(x) \neq 0$ , then we can divide both sides by $g(x)$ :

$f'(x)=\frac{0}{g(x)}$

$f'(x)=0$

This implies $f(x)$ is constant.

So we have that $f(x)=c$ where $c$ is a real number.

Since $f(0)=1$ and $f(0)=c$ , then by transitive property $1=c$ .

So $f(x)=1$ .

Checking:

$h(x)=1 \cdot g(x)$

$h'(x)=g'(x)=1 \cdot g'(x)$

So the following conditions were met.

5 0

3 years ago

Solve for j in the literal equation h-4/j

igor_vitrenko [27]

Answer:

$h - 4 \div j = 0 \\ - 4 \div j = - h \\ 4 \div j = h \\ j = 4 \div h$

3 0

4 years ago

MatroZZZ [7]

Answer:

44 ft

Step-by-step explanation:

You would subtract 657 - 613

6 0

4 years ago