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Mekhanik [1.2K]
3 years ago
8

Which of the following grinding methods is best suited to a shorter cylindrical workpiece?

Computers and Technology
1 answer:
schepotkina [342]3 years ago
4 0
well i dont know but i would go with b :D

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Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
IgorLugansk [536]

Answer:

See explaination

Explanation:

include<bits/stdc++.h>

using namespace std;

typedef struct Node

{

int data;

struct Node *left,*right;

}Node;

bool search(Node *root,int data)

{

if(root==NULL)

return false;

if(root->data==data)

return true;

queue<Node*> q;

q.push(root);

while(!q.empty())

{

Node *temp=q.front();

q.pop();

if(temp->data==data)

return true;

if(temp->left)

q.push(temp->left);

if(temp->right)

q.push(temp->right);

}

return false;

}

Node *insert(Node *root,int data)

{

if(root==NULL)

{

Node *temp=new Node();

temp->data=data;

temp->left=NULL;

temp->right=NULL;

return temp;

}

if(data < root->data)

root->left=insert(root->left,data);

if(data>root->data)

root->right=insert(root->right,data);

return root;

}

Node *get_smallest_element_right_subtree(Node *root)

{

while(root && root->left!=NULL)

root=root->left;

return root;

}

Node *delete_node(Node *root,int data)

{

if(root==NULL)

return root;

if(data < root->data)

root->left=delete_node(root->left,data);

else if(data > root->data)

root->right=delete_node(root->right,data);

else

{

if(root->left==NULL) //If right only presents means - delete the curr node and return right node

{

Node *temp=root->right;

free(root);

return temp;

}

else if(root->right==NULL) //If left only presents means - delete the curr node and return let node

{

Node *temp=root->left;

free(root);

return temp;

}

else

{

Node *temp=get_smallest_element_right_subtree(root->right);

root->data=temp->data;

root->right=delete_node(root->right,temp->data);

}

return root;

}

}

void inorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

cout<<root->data<<" ";

inorder(root->right);

}

}

void postorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

inorder(root->right);

cout<<root->data<<" ";

}

}

void preorder(Node *root)

{

if(root!=NULL)

{

cout<<root->data<<" ";

inorder(root->left);

inorder(root->right);

}

}

int main()

{

fstream f;

string filename;

cout<<"\n\n1 - Input through File ";

cout<<"\n\n2 - Input through your Hand";

int h;

cout<<"\n\n\nEnter Your Choice : ";

cin>>h;

Node *root=NULL; // Tree Declaration

if(h==1)

{

cout<<"\n\nEnter the Input File Name : ";

cin>>filename;

f.open(filename.c_str());

if(!f)

cout<<"\n\nError in Opening a file !";

else

{

cout<<"\n\nFile is Being Read ........";

string num;

int value;

int node=0;

while(f>> num)

{

value=stoi(num);

root=insert(root,value);

node++;

}

cout<<"\n\nTree has been successfully created with : "<<node<<" Nodes"<<endl;

}

}

if(h==2)

{

int y;

cout<<"\n\nEnter the Total No of Input :";

cin>>y;

int i=1,g;

while(i!=y+1)

{

cout<<"\n\nEnter Input "<<i<<" : ";

cin>>g;

root=insert(root,g);

i++;

}

cout<<"\n\nTree has been successfully created with : "<<y<<" Nodes"<<endl;

}

if(h>=3)

{

cout<<"\n\nInvalid Choice !!! ";

return 0;

}

int n=0;

while(n!=6)

{

cout<<"\n\n\n1 - Insert Element";

cout<<"\n\n2 - Remove Element";

cout<<"\n\n3 - Inorder (LNR) Display ";

cout<<"\n\n4 - Pre (NLR) Order Display";

cout<<"\n\n5 - Post (LRN) Order Display";

cout<<"\n\n6 - Quit";

cout<<"\n\nEnter Your Choice : ";

cin>>n;

switch(n)

{

case 1:

{

int k;

cout<<"\n\nEnter Element to insert : ";cin>>k;

root=insert(root,k);

cout<<"\n\nElement Sucessfully Inserted !!!!!";

break;

}

case 2:

{

int k;

cout<<"\n\nEnter Element to Remove : ";

cin>>k;

if(search(root,k))

{

root=delete_node(root,k);

cout<<"\n\nValue Successfully Deleted !!!";

}

else

cout<<"\n\n!!!!!!!!!!!!!!!!!!!! No Such Element !!!!!!!!!!!!!!!!!!!!!!";

break;

}

case 3:

{

cout<<"\n\nThe Elements (LNR) are : ";

inorder(root);

break;

}

case 4:

{

cout<<"\n\nThe Elements (NLR) are : ";

preorder(root);

break;

}

case 5:

{

cout<<"\n\nThe Elements (LRN) are : ";

postorder(root);

break;

}

case 6:

{

break;

}

}

}

cout<<"\n\nBye!!!! See You !!!"<<endl;

7 0
4 years ago
If you've finished working with a data file but intend to work on it again during your work session, which button would you use
mariarad [96]
Hey there! Hello!

So, not sure if there's actually a button to "close out" a window to where you're able to reopen it again without having to go to where the file is located or go to recents in your application. Keep in mind that I'm on a MacBook, but I have worked on a Windows computer before. 

One thing you can do is minimize the window. Your program will remain open, but your window will remain out of your way until you decide to expand it again. This seems to be the closest thing possible to your description, but if you had something else in mind, I'd love to hear more details.

This won't be a good solution if you're looking to cut down on the energy that certain programs may be taking up while open, even if you're not using them. But in terms of getting the windows off your desktop, minimizing is the way to go. It also allows you to have documents/windows out of the way while still being able to work on other documents/windows in the program (i.e. Microsoft Word, Google Chrome, Pages, etc.)

Hope this helped you out! Feel free to ask me any additional questions you may have. :-)
5 0
3 years ago
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Using the syntax in section 2.3, write a command delete_all_rights (p, q, s). this command causes p to delete all rights the sub
aalyn [17]
<span>command delete_all_rights(p, q, s)
delete read from a[q, s];
delete write from a[q, s];
delete execute from a[q, s];
delete append from a[q, s];
delete list from a[q, s];
delete modify from a[q, s];
delete own from a[q, s];
end</span>
6 0
4 years ago
What is the name of the symbol that is used to classify and categorize information?​
igomit [66]

Answer:

A Hashtag

Explanation:

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A ___ is a node (or a device) that connects two different networks together and allows them to communicate.
stellarik [79]

Answer:

The answer is Hub

Explanation:

A hub, also called a network hub, is a common connection point for devices in a network. Hubs are devices commonly used to connect segments of a LAN. The hub contains multiple ports. When a packet arrives at one port, it is copied to the other ports so that all segments of the LAN can see all packets.

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