Answer:
negatives = []
zeros = []
positives = []
while True:
number = input("Enter a number: ")
if number == "":
break
else:
number = int(number)
if number < 0:
negatives.append(number)
elif number == 0:
zeros.append(number)
else:
positives.append(number)
for n in negatives:
print(n)
for z in zeros:
print(z)
for p in positives:
print(p)
Explanation:
Initialize three lists to hold the numbers
Create a while loop that iterates until the user enters a blank line
Inside the loop:
If the number is smaller than 0, put it in the negatives list
If the number is 0, put it in the zeros list
Otherwise, put the number in the negatives list
When the while loop is done, create three for loops to print the numbers inside the lists
Answer:
false, that shouldn't be a a priority to identify if they are or not.
Explanation:
Answer:
couple.py
def couple(s1,s2):
newlist = []
for i in range(len(s1)):
newlist.append([s1[i],s2[i]])
return newlist
s1=[1,2,3]
s2=[4,5,6]
print(couple(s1,s2))
enum.py
def couple(s1,s2):
newlist = []
for i in range(len(s1)):
newlist.append([s1[i],s2[i]])
return newlist
def enumerate(s,start=0):
number_Array=[ i for i in range(start,start+len(s))]
return couple(number_Array,s)
s=[6,1,'a']
print(enumerate(s))
print(enumerate('five',5))
Explanation:
Answer: 545 words per 35 mins
Explanation:
The answer is d torque because
