Answer:
Step-by-step explanation:
just remember that ![\sqrt{x} = x^{1/2} ....... \sqrt[3]{x} = x^{1/3} \\also that (x^{a})^{b} = x^{a*b}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%3D%20x%5E%7B1%2F2%7D%20%20.......%20%20%5Csqrt%5B3%5D%7Bx%7D%20%3D%20x%5E%7B1%2F3%7D%20%5C%5Calso%20%20that%20%28x%5E%7Ba%7D%29%5E%7Bb%7D%20%20%3D%20x%5E%7Ba%2Ab%7D)
1) x^3 = x^ (3/4) ===> FALSE
2) x^3/4 = x^3/4 ===> TRUE
3) x^3/4 = x^3/4 ===> TRUE
4) x^(4/3) = x^(4/3) ===> TRUE
Answer: I luv u too
Step-by-step explanation: Hope u have great day lol
Answer:
Step-by-step explanation:
<h3>Given</h3>
- H is the circumcenter of triangle BCD,
- BC = 18
- HD = 14
<h3>To find </h3>
<h3>Solution</h3>
- Triangle BHD is isosceles, therefore BH = HD
- Point E is midpoint of BC, therefore BE = 1/2BC
<u>Using Pythagorean, finding the value of EH:</u>
- EH = √(BH² - BE²) = √(14² - (18/2)²) = √(196 - 81) = √115 = 10.72
