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EastWind [94]
3 years ago
15

Which statements are true? PLEASE HELP

Mathematics
1 answer:
hram777 [196]3 years ago
6 0

Answer:

XW = SR THATS IT I THINK??

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What is the value of x? Leave your answer in simplest radical form.
OleMash [197]

Step-by-step explanation:

By using Pythagoras theoram,

x²= (6)²+(4)²

{x}^{2}  = 36 + 16

{x}^{2}  = 52

x =  \sqrt{52}

x = 2 \sqrt{13}

optionD

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3 years ago
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Find the area please and will make brainliest
puteri [66]
To find the area of the trapezoid, we only need the quantities a1 (long base), a2(short base) and h(height).

Area=(1/2)(a1+a2)*h
=(1/2)(9.9+4.7)(5.6)
=40.88 mm ²

Not sure what's expected to give for "type".  Perhaps trapezoid or trapezium.

4 0
3 years ago
The area of a circle (A) is given by the formula A= pi*r to the second power, where r is the radius. The formula to find r is _.
podryga [215]

Answer:

<u>The correct option for the first blank is A. (A/pi) to the power of 1/2</u>

<u>The correct option for the second blank is A. 4.15</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the questions correctly:

Area of a circle (A) = π * r², where r = radius

2. The formula to find r is ________________:

A = π * r²

r² = A/π

√r² = √ A/π

r =  √A/π

<u>r =  A/π∧(1/2) or  (A/pi) to the power of 1/2. </u>

<u>The correct option for the first blank is A. (A/pi) to the power of 1/2</u>

3. if A = 54 centimeters squared, and pi = 22/7, r is _ centimeters.

We use the formula we got for the first blank, this way:

r =  (A/pi) to the power of 1/2

Replacing with the real values, we have:

r = (54/(22/7)) to the power of 1/2

r = 17.2 to the power of 1/2

r = √17.2 = 4.15 (Rounding to the next hundredth)

<u>The correct option for the second blank is A. 4.15</u>

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3 years ago
Use the diagram to help you solve the problem. Mark is a receptionist for Exclusive Auto Sales. His base salary is $21,000. He h
olga55 [171]
The answer is 22,260

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3 years ago
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Question <br> -6x+9+6x-13=
emmainna [20.7K]

Answer:

I get 4 as the answer

=four

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