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4 years ago

Tanya drove 3 1/2 hours and used 1/3 tank of gas. For how long could Tanya drive using 1/2 tank of gas?

1 answer:

7 0

She could drive for 10.5 hours with a full tank of gas before running out
or she could drive another 7 hours with her current gas ammount

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PLEASE HELP 20 POINTS

Illusion [34]

80% of the number 64 is 51.2

7 0

4 years ago

Kimberly sells handmade jewelry online, charging one price for bracelets and another price for necklaces. This table shows how m

kenny6666 [7]

Bracelet cost = b
Necklace cost = n

15b + 8n = 500
19b + 24n = 980

Elimination method x -3
-45b - 24n = -1500
19b + 24n = 980

-26b = -520
b = $20 bracelets

Plug back in
19(20) + 24n = 980
380 + 24n = 980
24n = 600
n = $25 necklaces

Check:
15(20)+ 8(25)= 500
300 + 200 = 500
500 = 500 :)

5 0

3 years ago

Sallie Woo worked these hours last week: Monday, 10; Tuesday, 8 1/4; Wednesday, 9 1/2; Thursday, 6; Friday, 8; Saturday, 5. Sall

almond37 [142]

Answer:

Her pay for the week= $ 611.325

Step-by-step explanation:

Sallie is paid $ 11.40 per hour for regular hours.

The total regular hours worked during the week are

Monday + Tuesday + Wednesday + Thursday+ friday = 8 + 8+ 8+6+8= 38 hours

She works overtime during the week

Monday + Tuesday + Wednesday = 2+ 1/4+ 1 1/2= 2+ 1/4 + 3/2

= 8 +1+ 6/4=15/4 = 3 3/4 hours

Over the weekend she works five hours .

So the total pay would be

$ 11.40( 38 ) + $ 11.40( 1.5) ( 15/4) + $ 11.40 ( 2) ( 5)

= 433.2 + 64.125 + 114.0

= $ 611.325

3 0

3 years ago

The membership fee for joining a local indoor trampoline park is $24 per year. The

Zigmanuir [339]

Answer:

calculator g

Step-by-step explanation:

5 0

3 years ago

Simplifying rational expressions <br> x^2-16/x^2+6x+8 = x-4/x+2<br> x^2-x-6/x^2-3x-10 = x-3/x-5

enot [183]

$\dfrac{x^2-16}{x^2+6x+8}$

Decompose the numerator and denominator into multipliers

To simplify the numerator we use the formula of difference of squares

$x^2-y^2=(x-y)(x+y)$

$x^2-16=(x-4)(x+4)$

To decompose the denominator into multipliers solve the square equation

$x^2+6x+8=0\\D=6^2-4*8=4=2^2\\x_1=\dfrac{-6+2}{2} =-2\\x_2=\dfrac{-6-2}{2} =-4$

Formula for factoring a square equation

$(x-x_1)(x-x_2)$

Substituting the found roots of the equation into the formula

$(x-(-2))(x-(-4))=(x+2)(x+4)$

After simplifying the numerator and denominator we get a fraction

$\dfrac{(x-4)(x+4)}{(x+2)(x+4)}=\dfrac{x-4}{x+2}$ , so

$\dfrac{x^2-16}{x^2+6x+8}=\dfrac{(x-4)(x+4)}{(x+2)(x+4)}=\dfrac{x-4}{x+2}$

$\dfrac{x^2-x-6}{x^2-3x-10}$

Decompose the numerator and denominator into multipliers

To decompose the numerator into multipliers solve the square equation

$x^2-x-6=0\\D=(-1)^2-4*(-6)=25=5^2\\x_1=\dfrac{1+5}{2} =3\\x_2=\dfrac{1-5}{2} =-2$

Formula for factoring a square equation

$(x-x_1)(x-x_2)$

Substituting the found roots of the equation into the formula

$(x-3)(x-(-2))=(x-3)(x+2)$

To decompose the denominator into multipliers solve the square equation

$x^2-3x-10=0\\D=(-3)^2-4*(-10)=49=7^2\\x_1=\dfrac{3+7}{2} =5\\x_2=\dfrac{3-7}{2} =-2$

Formula for factoring a square equation

$(x-x_1)(x-x_2)$

Substituting the found roots of the equation into the formula

$(x-5)(x-(-(-2))=(x-5)(x+2)$

After simplifying the numerator and denominator we get a fraction

$\dfrac{(x-3)(x+2)}{(x-5)(x+2)}=\dfrac{x-3}{x-5}$ , so

$\dfrac{x^2-x-6}{x^2-3x-10}=\dfrac{(x-3)(x+2)}{(x-5)(x+2)}=\dfrac{x-3}{x-5}$

Hello from Russia:^)

6 0

3 years ago

Tanya drove 3 1/2 hours and used 1/3 tank of gas. For how long could Tanya drive using​ 1/2 ​tank of gas?

Tanya drove 3 1/2 hours and used 1/3 tank of gas. For how long could Tanya drive using 1/2 tank of gas?