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julsineya [31]
3 years ago
9

When A is changing at a rate of -0.100 M⋅s−1 , how fast is B changing?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
6 0
The rate of change of B is twice that of A, so:
rate of change of B = 2 x -0.1
rate of change of B = -0.2 M/s
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Identify the standard metal cations in the active components of soaps
rjkz [21]
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Soap<span> is a </span>salt<span> of a </span>fatty acid. When soap have sodium and potassim cations, that is toilet soap and when soap have magnesium and calcium cations, that soap is called <span>metallic soap.</span>
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4 years ago
Which method of separation would be most appropriate for separating a mixture of water and alcohol?(1 point)
Gelneren [198K]

Answer:

fractional distillation  is the correct answer

Explanation:

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2 years ago
I NEED HELP PLEASE! :)
riadik2000 [5.3K]

Answer:

C_{21} H_{23} NO_{5}

Explanation:

First thing is we have assume all the percents are grams so we have

68.279g C, 6.2760g H, 3.7898g N, and 21.656g O

Now convert each gram to moles by dividing the the molar mass of each element

68.279g/12.01g= 5.685 moles of C

6.2760g/1.01g= 6.214 moles of H

3.7898g N/14.01g= 0.271 moles  of N

21.656g O/ 16.00g= 1.354 moles of O

Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....

5.685 moles/0.271 moles ------> ~21 C

6.214 moles/0.271 moles --------> ~23 H

0.271 moles  / 0.271 moles  ---------> 1 N

1.354 moles/ 0.271 moles ----------> ~5 O

So the empirical formula is C21H23NO5 C_{21} H_{23} NO_{5}

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3 years ago
Difference between flammable and combustible
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umka21 [38]

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The air is indeed predominantly a mixture of gaseous elements. The most abundant gas in the air being the nitrogen with 78.9%, oxygen with 20.95%, argon 0.93%, and carbon dioxide 0.04%, with lesser amounts of other gases also be present in it. The water vapor is also present in the air, though it is variable, being around 1% at sea level, but only 0.4% over the entire atmosphere.

3 0
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