Answer:
During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable. ( B )
During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not. ( C )
Explanation:
<u>The major Differences between The Zinc mercury cell and Lithium-iodine cell are :</u>
During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable. and
During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.
Given the relationship below,
Δ G = -nFE
E = emf of cell , G = free energy.
This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable
Answer:
200 liters of fluoridated drinking water would have to be consumed by as person to reach the toxic level.
Explanation:
Toxic level of fluoride ions = 0.2 g per 70 kg body weight
Concentration of fluoride ions in drinking water = 1 mg/ L = 0.001 g/L
1 mg = 0.001 g
Let the volume of drinking water consumed by person to reach the toxic level of fluoride concentration be V.
For 70 kg body weight 0.2 grams of fluoride ions will be toxic.
200 liters of fluoridated drinking water would have to be consumed by as person to reach the toxic level.
The Density would be 1.84
<u>Given:</u>
Concentration of NaClO = 0.037 M
ka (HClO) = 4.0*10⁻⁸
<u>To determine:</u>
The pH of the NaClO solution
<u>Explanation:</u>
The hydrolysis of the weak base can be represented by the ICE table shown below-
ClO- + H2O ↔ HClO + OH-
Initial 0.037M 0 0
Change -x +x +x
Equilibrium (0.037-x) x x
kb = kw/ka = [HClO][OH-]/[ClO-]
10⁻¹⁴/4*10⁻⁸ = x²/(0.037-x)
x = [OH-] = 9.62*10⁻⁵
p[OH-] = -log[OH-] = -log [9.62*10⁻⁵] = 4.02
pH = 14-p[OH-] = 14 - 4.02 = 9.98
Ans: pH of the solution is 9.98
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