Answer:
48 amino acids
Explanation:
The wild type gene codes for a protein with 100 amino acids. One amino acid is encoded by one triplet code of the gene. This means that the wild type gene has a total 100 triplets or 300 nucleotides to code for a protein of 100 amino acid. Mutation in this protein has introduced the code "UAA" at the 49th codon. The code "UAA" is a stop codon. Therefore, the mRNA transcribed from the mutant allele would code for a protein having 48 amino acids as the protein synthesis will be stopped once the stop codon at the 49th position is read.
Answer:
compound light microscope
Explanation:
an amoeba is a microscopic unicellular protist
The answer is budding. IN this type of asexual reproduction,
the offspring are genetically identical
to the parent. Examples of an organism that
reproduces by budding include hydra,
starfish, corals, and sponges. Yeast, fungi, also reproduce
asexually by budding.