This is called selective breeding
hope this helped!
Answer:
at its typical resting length.
Explanation:
Muscle fibers are elongated cells that can have one or more nuclei. They will form muscle tissues, which can be of three types: striated cardiac muscle, skeletal striated muscle or smooth muscle, each having its own functional and morphological characteristics. However, these types of muscle fibers have in common the ability to generate movement by contraction.
Contraction occurs at the moment of maximum tension of these muscle fibers and a muscle fiber develops its maximum tension when it is at its typical resting length before being stimulated.
Answer:
Explanation:
A. Inactivation of an enzyme that degrades M-Cyclin.
M-phase cyclins form M-CDK complexes and drive the cell's entry into mitosis from G2 phase as non-degradation of M-Cyclin resulting from inactivated enzyme can only result in constitutive entry of the cell in to M phase instead cell cycle being arrested at G2 phase,
B. Inactivation of the Wee-1 kinase.
Wee1 is a nuclear kinase that plays a key role in regulating cell cycle progression. Wee1 inhibits the entry of the cell into M phase by inhibiting Cdk1. Wee1 phosphorylates Cdk1 there inhibiting the kinase activity of Cdk1 which is essential for progression from G2 to M phase. As such any mutation of wee1, and the resulting loss of activity will result in premature entry of cells into M phase instead of getting arrested at the G2 phase resulting in smaller yeast cell.
C. Inactivation of the Cdc25 phosphatase
CDC25 phosphatases removes inhibitory phosphate residues from cyclin dependent kinases resulting in the activation of CDKs which causes the cells in G2 phase to entry to M phase. Mutation in CDC25 phosphates removes the ability of CDC25 to remove phosphate residues from CDKs thus preventing the entry into M-phase.
Therefore, mutant phenotype of cell cycle arrest prior to M phase can only result form mutation in
Cdc25 phosphatase(option 3)
Answer:
d. The species diversity of plot 2 is greater than that of plot 1.
Explanation:
Species diversity of an area depends on its species richness and species evenness. Species richness is the number of species present in that area. Species evenness measures how evenly these species are distributed.
Here, both plot 1 and plot 2 have same number of species. They both have four species of trees ( maple, birch, oak and pine) hence their species richness is same. However plot 1 has 85% maple trees and the rest three species make the remaining 15%. Plot 2 has more even distribution as 35% of trees are maple trees and birch and oak also have similar frequency with 25% and 35% respectively. Hence, plot 2 has more evenness.
Species diversity depends on both richness and evenness. Since plot 1 and 2 have same richness but plot 2 has more evenness, plot 2 has more species diversity than plot 1.
